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  #1  
Old September 28th, 2005, 02:52 PM
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Question 2 New To have a Clue

I am a complete novice in C++ as this is my first programming class ever. I am completely stuck on this problem:

Develop a progrm which displays all possible ways to break up a $100 bill. It should be formatted as shown:

No fifity twenty ten five two one
*** *** ***** *** *** *** ***
1 1 1 2 1 2 1


The example shows these add up to 100.

Print out the total number of possible combinations.




OK, I'm not asking for someone to write this, but I need some direction. Our prof is under the impression that self-learning is the way to teach. I've never seen an example program that prints out in columns like he's asking. Would I use a "for" or "if" or "while" loop or "else"? I really have no clue where to start.
I can understand the logic that it should start by printing 2 fifties, then next line 1 fifty, 2 twenties, 1 ten...or am I looking at that the wrong way? ANY help would be appreciated. It would be a lot easier if the prof actually explained this stuff. Thanks.

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Old September 28th, 2005, 03:39 PM
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Printing in columns is easy using the printf() statement. You can specify the minimum length of a variable printed by adding a number between the percent sign (%) and the type (d for an integer, f for a float, etc).
The following example will print all numbers from 0 to 24 in a 5 by 5 square, where every number takes up 2 digits, with one digit in between:
cpp Code:
Original - cpp Code
  1. #include <stdio.h>
  2.  
  3. int main(void)
  4. {
  5.     int i;
  6.     for(i = 0; i < 25; i += 5)
  7.         printf(" %2d %2d %2d %2d %2d \n", i, i+1, i+2, i+3, i+4);
  8.  
  9.     return 0;
  10. }


As for the assignment, the best way to do this is write a recursive function, that takes two arguments, a value and a denomination,
The function should go through all possible amounts that can be made with that denomination specified, and call itself again, with the remaining value and the next lower denomination. Unless denomination is 1, in which case the current combination should be printed.

I know this explanation can be a bit fuzzy if you don't know what recursion is, but in that case, it would be a good thing to go to your teacher and ask him to explain recursion a bit.

Hope this gets you on your way
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Last edited by Itsacon : September 28th, 2005 at 04:07 PM.

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Old September 28th, 2005, 03:55 PM
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Ok, I've got a working version, so if you're really stuck, just say.

Be aware that there are 4562 different ways to break up that 100 dollar bill...

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Old September 28th, 2005, 04:10 PM
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Please do post your version. I would like to see if what you have is anything similar to what we have been taught. I've been searching through books for days trying to figure this one out. That number seems awful high for where we are...and I have never heard of recursion, so I'll have to look it up. Thanks for the advice.







Quote:
Originally Posted by Itsacon
Ok, I've got a working version, so if you're really stuck, just say.

Be aware that there are 4562 different ways to break up that 100 dollar bill...

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Old September 29th, 2005, 12:37 AM
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Recursion is, simply put, breaking up a problem into smaller, decreasing steps.

For instance, calculating x! (a mathematical expressiong meaning x * x-1 * x-2 *..... * 2 * 1) can easily be done by recursion:
cpp Code:
Original - cpp Code
  1. int fac(int x)
  2. {
  3.     if(x == 1)
  4.         return 1;
  5.     else
  6.         return x * fac(x - 1);
  7. }


I'll post my solution later today, if you still can't figure it out.

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Old September 29th, 2005, 12:12 PM
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Post Solution

Ok, here's my solution.

Expanded it a bit to optionally take the amount from the command line, but when called without parameters, it defaults to 100 dollars.

See if you can figure out what makes it tick.
cpp Code:
Original - cpp Code
  1. #include <stdio.h>
  2. #include <stdlib.h>
  3.  
  4. // global variable to store the set we're currently working on
  5. int amounts[6];
  6.  
  7. // recursive function, takes a value, a bill to start at, and the number of options so far.
  8. int calculate_options(int value, int denom, int counter)
  9. {
  10.     // set possible denominations
  11.     static int vals[] = {1, 2, 5, 10, 20, 50};
  12.    
  13.     // at the 1 dollar bill yet?
  14.     if(denom > 0)      // no, for all the possible amounts the current bill fits in the current value, get all possible sub-amounts.
  15.     {
  16.         for(amounts[denom] = 0; value - amounts[denom] * vals[denom] >= 0; amounts[denom]++)
  17.             counter = calculate_options((value - amounts[denom] * vals[denom]), (denom - 1), counter);
  18.     }
  19.     else                // yes, output current set of values
  20.     {
  21.         // another option completed, increment counter
  22.         counter++;
  23.         // print the current set of bills
  24.         printf(" %2d * %5d * %6d * %3d * %4d * %3d * %3d \n", counter, amounts[5], amounts[4], amounts[3], amounts[2], amounts[1], value);
  25.     }
  26.     return counter;
  27. }
  28.  
  29. // main, takes arguments to read the command line
  30. int main(int argc, char **argv)
  31. {
  32.     // declarations
  33.     int bill, counter;
  34.  
  35.     // see if there's a value on command line
  36.     if(argc == 1)   // no, default to 100
  37.         bill = 100;
  38.     else            // yes, read value
  39.         bill = atoi(argv[1]);
  40.  
  41.     // print table header
  42.     printf(" No * fifty * twenty * ten * five * two * one \n");
  43.     printf("**********************************************\n");
  44.  
  45.     // call function
  46.     counter = calculate_options(bill, 5, 0);
  47.  
  48.     // print number of possibilities
  49.     printf("There are %d different ways to break up %d dollars\n", counter, bill);
  50.  
  51.     // exit
  52.     return 0;
  53. }

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Old September 29th, 2005, 01:43 PM
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Now do it for Canada... we do'nt have $1 or $2 bills.

Recursion, simple-r put... a function is recursive when it calls itself.
Keep in mind, there needs to be a way out... as in Itsacon's code, IF (something) call_myself ELSE print something
Otherwise you end up in an infinite loop.

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Old September 29th, 2005, 02:19 PM
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I bet you have 1 and 2 dollar coins...
Same here in europe... Only we call them euros....

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Old September 29th, 2005, 03:58 PM
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Thanks for the help and explanations! I will go through it with a fine-toothed comb. It looks like we haven't gone over some of this yet. I will discuss this with the prof. Thanks.

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Old September 29th, 2005, 04:26 PM
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@ Itsacon or MadCowDzz ???

Another side question, How would you substitute the printf, for a cout<< statement or is that even possible to do and still keep the same functionality? Just wondering

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Old September 30th, 2005, 12:21 AM
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Quote:
Originally Posted by Geo.Garnett
Another side question, How would you substitute the printf, for a cout<< statement or is that even possible to do and still keep the same functionality? Just wondering
#include <iostream>

Then just use:

cout<< "text" << variable_name << "more text" << another_var_name << "etc....";
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Old September 30th, 2005, 01:04 AM
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B-Con, that way, you can't define the width of the variables (which I suppose is what Geo meant)

This can be done in several ways:
cpp Code:
Original - cpp Code
  1. #include <iostream>
  2. #include <iomanip>
  3. using namespace std;
  4.  
  5. int main()
  6. {
  7.     int i;
  8.  
  9.     // first, there is the width() method of cout:
  10.    
  11.     for(i = 5; i < 15; i++)
  12.     {
  13.         // this will output i width a minimum width of 2 characters
  14.         cout.width(2);
  15.         cout << i << " ";
  16.     }
  17.     cout << "\n";
  18.  
  19.     // this is a problem with multiple parameters though:
  20.  
  21.     for(i = 5; i < 15; i += 2)
  22.     {
  23.         // note that here only the first i is outputted with a width of 2, the second is outputted normally
  24.         cout.width(2);
  25.         cout << i << " " << (i + 1) << " ";
  26.     }
  27.     cout << "\n";
  28.  
  29.     // an alternative is the setw() function:
  30.     // note that for this you need the <iomanip> library
  31.    
  32.     for(i = 5; i < 15; i += 2)
  33.     {
  34.         // here both parameters are printed with width 2
  35.         cout << setw(2) << i << " " << setw(2) << (i + 1) << " ";
  36.     }
  37.     cout << "\n";
  38.  
  39.     return 0;
  40. }
Comments on this post
Geo.Garnett agrees: Thats exactly what I meant, I'm just not a good explainer sometimes. =)
B-Con agrees: My bad, didn't catch that

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Old September 30th, 2005, 02:29 AM
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Thanks for your help Itsacon, & Bcon. That is exactly what I was looking for Itsacon. When using C functions like printf I know is available to C++ but like I said I started learning in C++ and that's what most of the books taught first other than printf, so for the past four months of my learning I have been using cout<< for all my programs output. I am just now going into C stuff because I realized those books I read left out a lot about C and being that C++ is just its superset I think it would have been better of me to learn C first
But no biggie. Thanks again ya'll, " who needs a mentor when I got all you guyz to help me out when ever I need it " <Thanks>

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Old September 30th, 2005, 03:08 AM
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You may have noticed that on most of my examples, I use pure C syntax, I do this for several reasons:
  • It's easier to read, especially for beginners
  • I find it easier to remember the C libraries than the C++ libraries.
  • gcc is easier to type than g++

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Old September 30th, 2005, 04:24 AM
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I'm back insomnia has me again lol. Well, let me ask you this, what language do you use to program in and what types of things do you program, just out of curiosity. The new book I got goes through C examples first so you have a good base when they start to teach you C++, its a little repeditive but it seems, like you say, easier.

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Old September 30th, 2005, 04:33 AM
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For my work, I program web interfaces and database applications. Mostly in PHP/MySQL

For my hobby, I do other people's homework on devarticles.com, in all kinds of lanquages

For my study, I do microcontroller development in assembler, C, C++ etc. Also some normal (PC) applications, mostly in C/C++.

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Old September 30th, 2005, 04:42 AM
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LOL to that second one.
Sounds interesting, I hope to be there some day =). Im not stalking you or nothing but I have just been having fun tracking your posts, mostly because a lot of my questions lately have been either directed to you or answered by you lol.

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Old September 30th, 2005, 04:44 AM
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Gives me something to do...

Want to join my fanclub?

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Old September 30th, 2005, 04:52 AM
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LOL, but seriously really lol.

But for real this time its bed time for me or I think I'm gonna have an aneurysm.

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Old September 30th, 2005, 05:17 AM
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  #21  
Old September 30th, 2005, 05:33 AM
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ALRIGHT Im in

Oh ya bed... forgot

It's almost seven AM now might as well suck it up and try to make it through the day now.

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  #22  
Old September 30th, 2005, 05:36 AM
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Auch... anything important planned for today?

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  #23  
Old September 30th, 2005, 05:53 AM
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Na, not much planned today. Most of the same stuff. I have the luxury right now of concentrating on school, but all the classes I take so far aren't about programming so they kinda take a back seat to my little independent study of the C/C++ language. That's why I'm always here sucking up all the information I can get, you guys are like my secondary Professors right now.
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SWEET

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LMBO so hard when I saw your signature, I think I wet myself!!

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