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  #1  
Old June 19th, 2007, 03:58 PM
Aherald117 Aherald117 is offline
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C++ code has no errors but wont work.Help Please Thanks

Here is the problem, followed by my c++ program


3. To design a square timber column in a structure, three formulas must be satisfied:

a. Buckling load:

Maximum load = (.3  E  Area) / (Length / Width)2

b. Compressive stress:
Maximum load = Area  Maximum compressive strength

c. Slenderness limit:

Length / Width  50

where :

E = the modulus of elasticity = 1,700,000 lb/in2
Area = the cross sectional area in square inches
Maximum compressive strength = 445 lb/in2

for a Douglas Fir tree.

Write a program called “hw3b.cpp” that uses these three formulas to give an initial design to a structural engineer. Assume the columns to be used are square and are available in intervals of 2 inches (i.e. 2 by 2, 4 by 4, 6 by 6 and so on). Have the output look like the following:

Please enter the expected load in pounds> 9000
Please enter the length of the column in inches> 120

….Testing a beam with Area of 2.0 by 2.0 inches – Failed the tests
….Testing a beam with Area of 4.0 by 4.0 inches – Failed the tests
….Testing a beam with Area of 6.0 by 6.0 inches – Passed the tests

For a load of 900.0 pounds and a length of 120.0 inches, recommended square beam has sides of 6.0 inches

Write a function for each of the three tests. Hint: Have each function return a 1 (TRUE) if the test is passed a 0 (FALSE) otherwise.

Here is my code without a function or outfile text and it wont work, does any1 know why?


//Alex Herald//
//GEU111//

#include <iostream> //input output//
#include <cmath> //math functions//
#include <fstream>
using namespace std; //cin cout//'

int main(void)
{
ofstream outfile;
outfile.open("HW3b.txt");
double E = 1700000; //the modulus of elasticity//
double MCS = 445; //maximum compressive strength//
double area; //the cross sectional area in square inches
double l,p;
int w;
double Bl,Cs,Sl;
int sum;
int buck_load, comp_str, slend_limit;


cout <<"Please enter the expected load in pounds -->";
cin >> p;

cout <<"Please enter length of the column in inches -->";
cin >> l;

for(w = 2; sum!=3; w = w+2){

area= w*w;
Bl = (.3 * E * area) / (l/w)*(l/w);
Cs = (area * MCS);
Sl = (l/w);

if (Bl > p) {
buck_load= 1;
outfile <<"Pass"<<endl;
}
else{
buck_load = 0;
cout << "Fail" << endl;
}
if (Cs > p) {
comp_str = 1;
cout <<"Pass"<< endl;
}
else{
comp_str = 0;
cout << "Fail"<<endl;
}
if (l <= 50) {
slend_limit = 1;
cout << "Pass" << endl;
}
else{
slend_limit = 0;
cout << "Fail"<< endl;
}
sum = Bl + Cs + Sl;
}

return(0);
}

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  #2  
Old June 19th, 2007, 05:01 PM
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if you look at your for loop

for(w = 2; sum!=3; w = w+2){

you sill see that it is set to loop until sum equals 3. well, at the beginning of the program, you set sum=3, so it will never enter the for loop. modify the conditions of your for loop.

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  #3  
Old June 19th, 2007, 05:06 PM
Aherald117 Aherald117 is offline
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Ok i did that but it still doesnt run correctly, do you see anything else wrong with it?

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  #4  
Old June 19th, 2007, 05:12 PM
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well, in the first section of the for loop, the line:

sum = buck_load + comp_str + slend_limit;

buck_load, comp_str, and slend_limit are never set to any value, so you are setting sum = NULL

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  #5  
Old June 19th, 2007, 05:18 PM
Aherald117 Aherald117 is offline
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First off I want to say thanks for responding to my questions.

In my original program i had E and MCS as doubles but since i know what they are i defined them, however now i get these errors:




\\WINUSERS\HOMES\WinFiles\My Documents\Alex's C++ Work\Assignment 3\HW3btest.cpp(32) : error C2143: syntax error : missing ')' before ';'
\\WINUSERS\HOMES\WinFiles\My Documents\Alex's C++ Work\Assignment 3\HW3btest.cpp(32) : error C2059: syntax error : ')'
\\WINUSERS\HOMES\WinFiles\My Documents\Alex's C++ Work\Assignment 3\HW3btest.cpp(32) : error C2100: illegal indirection
\\WINUSERS\HOMES\WinFiles\My Documents\Alex's C++ Work\Assignment 3\HW3btest.cpp(32) : warning C4552: '*' : operator has no effect; expected operator with side-effect
\\WINUSERS\HOMES\WinFiles\My Documents\Alex's C++ Work\Assignment 3\HW3btest.cpp(33) : error C2143: syntax error : missing ')' before ';'
\\WINUSERS\HOMES\WinFiles\My Documents\Alex's C++ Work\Assignment 3\HW3btest.cpp(33) : error C2059: syntax error : ')'
Error executing cl.exe.

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  #6  
Old June 19th, 2007, 05:33 PM
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repost your corrected code. wrap it in code tags to make it easier to read and throw a comment labeling line 32 and 33 of your code. im not exactly sure if im looking at the right lines in your code.

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  #7  
Old June 19th, 2007, 05:39 PM
Aherald117 Aherald117 is offline
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i did and the lines of error are concerned with these lines

Bl = (.3 * E * area) / pow(l/w,2);
Cs = (area * MCS);
Sl = (l/w);

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  #8  
Old June 19th, 2007, 05:43 PM
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if you compile again, you'll prolly see 3 errors for undefined varibles for the line

sum = buck_load + comp_str + slend_limit;

you need to change them to Bl, Cs, and Sl respectively

as far as the other errors, try just declaring them as doubles.

EDIT:

i.e.

Code:
double E = 1700000; //the modulus of elasticity//
double MCS = 445; //maximum compressive strength//

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  #9  
Old June 19th, 2007, 05:53 PM
Aherald117 Aherald117 is offline
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ok thanx, it ran, but it doesnt end, it keeps repeating pass fail pass fail etc. If you look at the problem, it has to end at the 6x6 because it meets the requirements. Thanx again very much

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Old June 19th, 2007, 05:54 PM
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no problem, and good luck finishing it up.

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  #11  
Old June 19th, 2007, 06:03 PM
daniel_g daniel_g is offline
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was gonna say something, but never mind. The right words just didn't come out...

Last edited by daniel_g : June 19th, 2007 at 06:12 PM.

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  #12  
Old June 19th, 2007, 06:12 PM
Aherald117 Aherald117 is offline
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According to the problem, if i set all the true statements equal to 1 then it should end the loop when w=6 because based on the problem it should end when the stud is 6X6 which is the third time through the loop if w is initially 2 and you add 2 each time it runs through. The reason it should end is because the third condition is met, the (Sl <= 50), making it pass all three tests. Does any1 know why it doesnt end?

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  #13  
Old June 19th, 2007, 06:35 PM
daniel_g daniel_g is offline
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Ok, here goes. First off, your program is always going to print 'fail' no matter what:
Code:
for(w = 2; sum!=3; w = w+2){
    area= w*w;
    Bl = (.3 * E * area) / pow(l/w,2);
    Cs = (area * MCS);
    Sl = (l/w);
    sum = buck_load + comp_str + slend_limit;

    if (Bl > p) {
        buck_load= 1;
        outfile <<"Pass";
    }
    else
        buck_load = 0;
    cout << "fail"; //This is outside the else statement

    if (Cs > p) {
        comp_str = 1;
        cout <<"Pass";
    }
    else
        comp_str = 0;
    cout << "Fail"; //This is outside the else statement
    if (Sl <= 50) {
        slend_limit = 1;
        cout << "Pass";
    }
    else
        slend_limit = 0;
    cout << "Fail"; //This is outside the else statement

I think you might be missunderstanding how to use if/else statements. If you do:
Code:
if(){
    //something here
}
else
    //thing1
//thing2

thing2 is always going to happen, regardless of if you go to the if, or the else statement. If you want it to happen only if the else statement is met, then use:
Code:
if(){//something here}
else{
    //thing1
    //thing2
}
//notice the brackets.

Now I don't know why your program isn't ending. Repost the code you have so far so we can take a look at it. I made only a couple changes to the one you originally posted, the output is all messed up, but it does end.

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  #14  
Old June 19th, 2007, 06:42 PM
Aherald117 Aherald117 is offline
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ok i updated it, and it still runs without end, any ideas? Really Appreciate the help

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  #15  
Old June 19th, 2007, 07:08 PM
daniel_g daniel_g is offline
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ok.
First thing:
Code:
          if (l <= 50) {
              slend_limit = 1;
              cout << "Pass" << endl;
          }

I'm pretty sure you meant if(Sl <=50){...}, right?

Second, if you ever want sum to be equal to 3, then define sum like this:
sum = buck_load + comp_str + slend_limit;

Do those changes, and your program will end. You might want to include a system("Pause"); at the very end.

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  #16  
Old June 19th, 2007, 07:17 PM
Aherald117 Aherald117 is offline
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ok it finally stopped but it brings me an out put of

fail
fail
fail
pass
pass
pass

but its suppose to say

fail
fail
pass

do you know why this is?

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  #17  
Old June 19th, 2007, 07:22 PM
daniel_g daniel_g is offline
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I see, what you need to do, is take all the cout<<'s out of the if else statements you already have(ie. erase all the cout<< you currently have inside the for loop).
Then, inside the for loop, at the very end of it, do this:
Code:
for(w = 2; sum!=3; w = w+2){
    //...
    sum = buck_load + comp_str + slend_limit;
    if(sum == 3){
        cout<<"Pass"; cout<<endl;
    }
    else{
        cout<<"Fail";
    }
}//end of for loop

Basically, just print the result once it's done checking everything on the for loop.

PS. I'm not good with physics, so I don't know why it runs more than 3 times..

Last edited by daniel_g : June 19th, 2007 at 07:26 PM.

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  #18  
Old June 19th, 2007, 07:30 PM
Aherald117 Aherald117 is offline
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Mystery solved, thanx so much for all of your assistance, the only other question i have is with how to make it useful as a function because im struggling with understanding how they work and my teacher suggested to me that i should solve the program first and then changed it to make it work like a function. Whats weird is i know how to use functions in Matlab and my teacher said its basically the same thing just with a different set up but i still dont understand it?

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Old June 19th, 2007, 07:50 PM
daniel_g daniel_g is offline
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Yeah, basically the same. Like in matlab, you open a new .mat document and start something like:
Code:
this_a_function(arg1, arg2, arg3)
 %%blah blah blah

and then you call it on the console screen by writing
>this_a_function(10,32,53)

On c++ is the same thing. except the console is the main() method. Here is an example:
Code:
#include <iostream>
using namespace std;

void myFirstFunction(){
    std::string myString = "Hello World -";
    cout<<myString;
}
void mySecondFunction(){
    std::string myString = "bye bye World";
    cout<<myString;
}

int main(void){
    myFirstFunction();
    mySecondFunction();
    system("Pause");
}

/*
 * The output should be: 
 * "Hello World - bye bye World"
 */
//note how the functions use the same variable 'myString',
//but the compiler does not get confused.

Basically, the purpose of a function, is to clean up the main() method, and be able to reuse the same variable name over and over without confusing the compiler.

Additionally, just like in matlab, the function can take arguments. For example:
Code:
#include <iostream>
using namespace std;

void myFirstFunction(std::string anArgument){
    std::string myString = anArgument;
    cout<<myString;
}

int main(void){
    myFirstFunction("Hello World");
}

/*
 * The output should be: 
 * "Hello World
 */


If you wanted to, you could place the whole for loop of your code inside a function, and then just call the function after you ask the user for the inputs. - But you would need to declare all variables as global, that is, take them out of the main method(), or just declare them inside the function.

Last edited by daniel_g : June 19th, 2007 at 07:57 PM.

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Old June 19th, 2007, 08:01 PM
Aherald117 Aherald117 is offline
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ok, i did something like this but i got a few errors
//Alex Herald//
//GEU111//

#include <iostream> //input output//
#include <cmath> //math functions//
#include <fstream>
using namespace std; //cin cout//'

double buck_load(double aa,double ee,double ll, double ww);
double comp_str(double aa,double mm);
double slend_limit(double ll, double ww);

int main(void)
{
ofstream outfile;
outfile.open("HW3b.txt");
double E = 1700000; //the modulus of elasticity//
double MCS = 445; //maximum compressive strength//
double area; //the cross sectional area in square inches
double l,p;
int w;
double Bl,Cs,Sl;
int sum;
int buck_load, comp_str, slend_limit;


cout <<"Please enter the expected load in pounds -->";
cin >> p;

cout <<"Please enter length of the column in inches -->";
cin >> l;

for(w = 2; sum!=3; w = w+2){

area= w*w;
Bl = (.3 * E * area) / (l/w)*(l/w);
Cs = (area * MCS);
Sl = (l/w);

if (Bl > p) {
buck_load= 1;
}
else{
buck_load = 0;
}
if (Cs > p) {
comp_str = 1;
}
else{
comp_str = 0;

}
if (Sl <= 50) {
slend_limit = 1;
}
else{
slend_limit = 0;
}
sum = buck_load + comp_str + slend_limit;

if (sum == 3){
cout<<"Pass"; cout<<endl;
outfile <<"...Testing a beam with area of" << w << "by" << w << "inches - Passed the tests";
}
else{
cout<<"Fail"<< endl;
outfile <<"...Testing a beam with area of" << w << "by" << w << "inches - Failed the tests";
}

}
return(0);
}

double buck_load(double aa,double ee,double ll, double ww){
return(.3 * E * area) / (l/w)*(l/w);
}
double comp_str(double aa,double mm){
return(area * MCS);
}
double slend_limit(double ll, double ww){
return (l/w);
}


the errors are

\\WINUSERS\HOMES\WinFiles\My Documents\Alex's C++ Work\Assignment 3\HW3btest.cpp(75) : error C2065: 'E' : undeclared identifier
\\WINUSERS\HOMES\WinFiles\My Documents\Alex's C++ Work\Assignment 3\HW3btest.cpp(75) : error C2065: 'area' : undeclared identifier
\\WINUSERS\HOMES\WinFiles\My Documents\Alex's C++ Work\Assignment 3\HW3btest.cpp(75) : error C2065: 'l' : undeclared identifier
\\WINUSERS\HOMES\WinFiles\My Documents\Alex's C++ Work\Assignment 3\HW3btest.cpp(75) : error C2065: 'w' : undeclared identifier
\\WINUSERS\HOMES\WinFiles\My Documents\Alex's C++ Work\Assignment 3\HW3btest.cpp(78) : error C2065: 'MCS' : undeclared identifier


and they concern the last few lines of code

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  #21  
Old June 19th, 2007, 08:31 PM
Aherald117 Aherald117 is offline
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can any1 help with this function?

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  #22  
Old June 19th, 2007, 08:54 PM
daniel_g daniel_g is offline
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I don't think you got how functions work just yet. Try these steps:

First step: Declare a function before the main() method, and call it in main:
Code:
#include <iostream>
using namespace std;

double buck_load(){}

main{
    double area, elasticity, etc;
    //...
    buck_load();
}

Second step: Decide how many arguments you need to take, define them in the function outside main, and set them inside main:
Code:
#include <iostream>
using namespace std;

double buck_load(double a, double e, double l2, double w2){
}

main{
    double area, E, l, w
    //...
    buck_load(area, E, l, w);
}

Then finish off details:
Code:
#include <iostream>
using namespace std;

double buck_load(double a, double e, double l2, double w2){
    return((.3 * e * a) / (l2/w2)*(l2/w2));
}

main{
    double area, E, l, w
    //...
    buck_load(area, E, l, w);
}

Now the function should work, but it doesn't really do much right now, inside main, treat it just like a variable:
Code:
#include <iostream>
using namespace std;

double buck_load(double a, double e, double l2, double w2){
    return((.3 * e * a) / (l2/w2)*(l2/w2));
}

main{
    double area, E, l, w
    //...
    Bl = buck_load(area, E, l, w);
    //...
}

//remember you had Bl = (.3 * E * area) / (l/w)*(l/w);
// instead,now you have  Bl = buck_load(area, E, l, w);

now repeat for every other function you want to create.

Last edited by daniel_g : June 19th, 2007 at 08:59 PM.

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  #23  
Old June 20th, 2007, 11:34 AM
Aherald117 Aherald117 is offline
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Thanks a lot for all the help, it finally works

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