Evaluating differ. parts of a single #.

Original - cpp Code #include <stdio.h> int main() { // declarations int firstvar, secondvar, thirdvar, fourthvar, initialcode; // a value for the initial code initialcode = 12345678; // calculate codes firstvar = initialcode / 100000; secondvar = (initialcode % 100000) / 100; // use modulo (remainder) to remove the part in front of the code, thirdvar = (initialcode % 100) / 10; // and divide to remove everything behind; fourthvar = initialcode % 10; // output printf("Original code: %8d\n", initialcode); printf("First 3 digits: %8d\n", firstvar); printf("Next 3 digits: %8d\n", secondvar); printf("2nd to last digit: %8d\n", thirdvar); printf("Last digit: %8d\n", fourthvar); // exit return 0; }

#include <stdio.h>
 
int main()
{
    // declarations
    int firstvar, secondvar, thirdvar, fourthvar, initialcode;
 
    // a value for the initial code
    initialcode = 12345678;
 
    // calculate codes
    firstvar = initialcode / 100000;
    secondvar = (initialcode %  100000) / 100;    // use modulo (remainder) to remove the part in front of the code, 
    thirdvar = (initialcode % 100) / 10;            // and divide to remove everything behind;
    fourthvar = initialcode % 10;
 
    // output
    printf("Original code:     %8d\n", initialcode);
    printf("First 3 digits:    %8d\n", firstvar);
    printf("Next 3 digits:     %8d\n", secondvar);
    printf("2nd to last digit: %8d\n", thirdvar);
    printf("Last digit:        %8d\n", fourthvar);
 
    // exit
    return 0;
} 

Original - cpp Code #include <stdio.h> #include <math.h> int get_digits(int code, int start, int length) { // start is the first digit you want (starting at 0 FROM THE RIGHT!), length is the number of digits you want // so get_digits(12345678, 2, 3) will return 456 return ((code / (int) pow(10, start)) % (int) pow(10, length)); } int main() { // declarations int firstvar, secondvar, thirdvar, fourthvar, initialcode; // a value for the initial code initialcode = 12345678; // calculate codes firstvar = get_digits(initialcode, 5, 3); secondvar = get_digits(initialcode, 2, 3); thirdvar = get_digits(initialcode, 1, 1); fourthvar = get_digits(initialcode, 0, 1); // output printf("Original code: %8d\n", initialcode); printf("First 3 digits: %8d\n", firstvar); printf("Next 3 digits: %8d\n", secondvar); printf("2nd to last digit: %8d\n", thirdvar); printf("Last digit: %8d\n", fourthvar); // exit return 0; }

#include <stdio.h>
#include <math.h>
 
int get_digits(int code, int start, int length)
{
    // start is the first digit you want (starting at 0 FROM THE RIGHT!), length is the number of digits you want
    // so get_digits(12345678, 2, 3) will return 456
    
    return ((code / (int) pow(10, start)) % (int) pow(10, length));
}
 
int main()
{
    // declarations
    int firstvar, secondvar, thirdvar, fourthvar, initialcode;
 
    // a value for the initial code
    initialcode = 12345678;
 
    // calculate codes
    firstvar = get_digits(initialcode, 5, 3);
    secondvar = get_digits(initialcode, 2, 3);
    thirdvar = get_digits(initialcode, 1, 1);
    fourthvar = get_digits(initialcode, 0, 1);
 
    // output
    printf("Original code:     %8d\n", initialcode);
    printf("First 3 digits:    %8d\n", firstvar);
    printf("Next 3 digits:     %8d\n", secondvar);
    printf("2nd to last digit: %8d\n", thirdvar);
    printf("Last digit:        %8d\n", fourthvar);
 
    // exit
    return 0;
}