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  #1  
Old June 26th, 2005, 12:58 PM
raywu raywu is offline
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how to modify the size of array in struct??

hi,
I get a question.
in my program, I have:

struct gogogo
{
char here[100];

};

but, the the size of "here" will be changed each time when I use it.

How can I difine this kind of array??

( the struct is required in this program )

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Old June 26th, 2005, 05:58 PM
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Use dynamic memory. Change "char here[100]" to be "char *here" then just allocate memory and set "here" equal to it.... ie:

C: here = malloc(size)
C++: here = new char[size]

And don't forget to deallocate the memory once you're done
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Old June 26th, 2005, 09:31 PM
raywu raywu is offline
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hi
this methd will pop up a error message window.

my code

struct dat
{
unsigned char* here[100];

}

dat get_dat;
get_dat.here = new unsigned char[ 800 ];
......
delete [] get_dat.here;


=======================================
sorry
the problem is raise by other functions

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Old June 27th, 2005, 02:08 AM
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struct dat
{
unsigned char* here;
}

don't make "here" an array and a pointer, otherwise it will be an array of pointers, and you only need one pointer

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Old July 8th, 2005, 08:03 PM
nishivision nishivision is offline
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simply use define statement.
which means after declaring header file
#define SIZE 100

and then while using struct write here[SIZE] and when u run ur program keep changing the SIZE .

or simply use the realloc

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Old July 27th, 2005, 05:11 PM
ubergeek ubergeek is offline
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if you're using c++ you could use a template:
Code:
 template<int size> struct gogogo
 {
 char here[size];
 };
 //...
 gogogo<100> hundred;
 gogogo<23> twenty_three;
 

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