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Syntax errors - Last Part of the program: Owner

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  #1  
Old December 1st, 2008, 10:02 AM
CDCAREY089 CDCAREY089 is offline
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Syntax errors - Last Part of the program: Owner
Okay. I have a couple of switches in this function and I was wondering how I can fix this part of the program because it brings up a jump to switch case error.


This is the header:

Code:
#ifndef JJAC_O_H
#define JJAC_O_H

class Users
{
  public:
    void users();
    void ownerNames( string, string, string, string );
    void viewExternal();
    void workExternal();
};

#endif





This is the class file:


Code:
#include <iostream>
#include <string>
#include <iomanip>
#include <cstdlib>
#include <fstream>
using namespace std;

#include "JJAC_O.h"

void Users::ownerNames( string own1, string own2, string own3, string own4 )
{
  own1 = "Jessica";
  own2 = "Jerald";
  own3 = "Adeola";
  own4 = "Ciara";
}

void Users::users()
{
  int code;

  cout << "Welcome to JJAC Gaming.\n"
         << "Please choose one of the following options:\n"
         << "1 - Player\n"
         << "2 - Employee\n"
         << "3 - Owner\n"
         << "4 - Exit\n";
cin >> code;

while( code != 4 )
{
  switch( code )
  {
    case 1:
      cout << "\nYou are not authorized to use this area."
             << "\nYou will be redirected to the exiting system.";
      break;

    case 2:
      int employeeCode;
      cout << "\nWelcome to JJAC Games - Employee Section.\n"
             << "\nFor security purposes, please input the company given code: ";
      cin >> employeeCode;

      switch( employeeCode )
      {
        case 1:
          char yesno;
          cout << "Welcome, Jessica Kennedy.\n"
                 << "Would you like to modify the employee files( y/n )? ";
          cin >> yesno;
          cout << endl;

          if( yesno == 'y' )
            cout << "\nAccessing data now . . . .\n"
                   << "\nUnable to access without password.\n"
                   << "\nRedirecting you to secondary menu . . .\n";
          break;

        case 2:
          char yesno2;
          cout << "Welcome, Jerald Dawson.\n"
                 << "Would you like to modify the employee files( y/n )? ";
          cin >> yesno2;
          cout << endl;

          if( yesno2 == 'y' )
            cout << "\nAccessing data now . . . .\n"
                   << "\nUnable to access without password.\n"
                   << "\nRedirecting you to secondary menu . . .\n";
          break;

        case 3:
          char yesno3;
          cout << "Welcome, Adeola Odunsi.\n"
                 << "Would you like to modify the employee files( y/n )? ";
          cin >> yesno3;
          cout << endl;

          if( yesno3 == 'y' )
            cout << "\nAccessing data now . . . .\n"
                   << "\nUnable to access without password.\n"
                   << "\nRedirecting you to secondary menu . . .\n";
          break;

        case 4:
          char yesno4;
          cout << "Welcome, Ciara Carey.\n"
                 << "Would you like to modify the employee files( y/n )? ";
          cin >> yesno4;
          cout << endl;

          if( yesno4 == 'y' )
            cout << "\nAccessing data now . . . .\n"
                   << "\nUnable to access without password.\n"
                   << "\nRedirecting you to secondary menu . . .\n";
          break;

        case 5:
          char yesno5;
          cout << "\nWelcome, current employee.\n"
                 << "Would you like to view information( y/n )?\n";
          cin >> yesno5;

          if( yesno5 == 'y' )
            viewExternal();
          break;

        case 6:
          cout << "\nWelcome, former employee."
                 << "\nYou need permission to access this information."
                 << "\nPlease see an owner in order to access the information."
                 << "\nThank you."
                 << "\nRedirecting you to secondary menu . . .\n";
          break;

       case 7:
         cout << "\nWelcome, new employee.\n"
                << "At this time, you need to view this information only\n"
                << "while a current employee or an owner is present.\n"
                << "\nThank you for your interests.\n";
         break;

       default:
         cout << "\nAn incorrect employee code was entered."
                << "\nEnter a correct code at prompt.\n";
         break;
    }

    case 3:
      string owner;

      string own1;
      string own2;
      string own3;
      string own4;

      ownerNames( own1, own2, own3, own4 );

      cout << "\nPlease enter password: ";
      cin >> owner;

      if( owner != own1 || owner != own2 || owner != own3 || owner != own4 )
      {
        int misspass = 1;

        while( misspass != 3 )
        {
          cout << "\nIncorrect password."
                 << "\nAttempt " << misspass << " of 3"
                 << "\nEnter a correct password: ";
          cin >> misspass;

          misspass++;
        }
      }

      if( owner == own1 || owner == own2 || owner == own3 || owner == own4 )
        cout << "Welcome, " << owner << ".\n"
               << "\nPlease enter data into the file: ";
      workExternal();
      break;

    default:
      cout << "Incorrect code. Try again:";
      break;
  }
}

void Users::workExternal()
{
  ofstream outJJACFile( "JJAC.dat" );

  if( !outJJACFile )
  {
    cerr << "File could not be opened.";
    exit( 1 );
  }

  double pay;
  string position;
  string name;

  cout << "Please enter the employee's name, position, and pay: ";
  cin >> name >> position >> pay;

  while( cin >> name >> position >> pay )
  {
    outJJACFile << name << ' ' << position << ' ' << pay;
    cout << "?";
  }
}

void Users::viewExternal()
{
  ifstream inJJACFile( "JJAC.dat", ios::in )

  if( !inJJACFile )
  {
    cerr << "File could not be opened.";
    exit( 1 );
  }

  cout << "\nPulling up data: \n"

  cout << "Name of Employee" << setw( 5 ) << "Position" << setw( 5 ) << "Pay"
       << endl << fixed << showpoint;

  do
  {
    cout << left << setw( 10 ) << name << setw( 13 ) << position
         << setw( 7 ) << setprecision( 2 ) << right << pay << endl;
  } while( inJJACFile >> name >> position >> pay )
}




These are the errors:


Code:
JJAC_O.cpp: In member function `void Users::users()':
JJAC_O.cpp:164: jump to case label
JJAC_O.cpp:136:   crosses initialization of `std::string own4'
JJAC_O.cpp:135:   crosses initialization of `std::string own3'
JJAC_O.cpp:134:   crosses initialization of `std::string own2'
JJAC_O.cpp:133:   crosses initialization of `std::string own1'
JJAC_O.cpp:131:   crosses initialization of `std::string owner'
JJAC_O.cpp:171: declaration of `void Users::workExternal()' outside of class is 
   not definition
JJAC_O.cpp:171: syntax error before `{' token
JJAC_O.cpp:174: `outJJACFile' undeclared (first use this function)
JJAC_O.cpp:174: (Each undeclared identifier is reported only once for each 
   function it appears in.)

Internal compiler error: Error reporting routines re-entered.
Please submit a full bug report,
with preprocessed source if appropriate.
See <URL:http://bugzilla.redhat.com/bugzilla/> for instructions.




Please help if possible. Thank you.
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  #2  
Old December 1st, 2008, 03:45 PM
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Bobidybob Bobidybob is offline
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dont forget to put a break after the nested switch in case 2

Code:
case 2:
      int employeeCode;
      cout << "\nWelcome to JJAC Games - Employee Section.\n"
             << "\nFor security purposes, please input the company given code: ";
      cin >> employeeCode;

      switch( employeeCode )
      {
      //blah blah blah
      }
      break;
__________________
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  #3  
Old December 1st, 2008, 10:04 PM
CDCAREY089 CDCAREY089 is offline
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Okay. That didn't work so I took out the default case, I know it's a bad idea, and after solving the errors I knew got these syntax errors:


Code:
JJAC_O.cpp: In member function `void Users::users()':
JJAC_O.cpp:169: declaration of `void Users::workExternal()' outside of class is 
   not definition
JJAC_O.cpp:169: syntax error before `{' token
JJAC_O.cpp:172: `outJJACFile' undeclared (first use this function)
JJAC_O.cpp:172: (Each undeclared identifier is reported only once for each 
   function it appears in.)
JJAC_O.cpp: In member function `void Users::viewExternal()':
JJAC_O.cpp:216: syntax error before `}' token
JJAC_O.cpp:211: confused by earlier errors, bailing out


for this program:



Code:
#include <iostream>
#include <string>
#include <iomanip>
#include <cstdlib>
#include <fstream>
using namespace std;

#include "JJAC_O.h"

void Users::ownerNames( string own1, string own2, string own3, string own4 )
{
  own1 = "Jessica";
  own2 = "Jerald";
  own3 = "Adeola";
  own4 = "Ciara";
}

void Users::users()
{
  int code;

  cout << "Welcome to JJAC Gaming.\n"
         << "Please choose one of the following options:\n"
         << "1 - Player\n"
         << "2 - Employee\n"
         << "3 - Owner\n"
         << "4 - Exit\n";
cin >> code;

 while( code != 4 )
{
  switch( code )
  {
    case 1:
      cout << "\nYou are not authorized to use this area."
             << "\nYou will be redirected to the exiting system.";
      break;

    case 2:
      int employeeCode;
      cout << "\nWelcome to JJAC Games - Employee Section.\n"
             << "\nFor security purposes, please input the company given code: ";
      cin >> employeeCode;

      switch( employeeCode )
      {
        case 1:
          char yesno;
          cout << "Welcome, Jessica Kennedy.\n"
                 << "Would you like to modify the employee files( y/n )? ";
          cin >> yesno;
          cout << endl;

          if( yesno == 'y' )
            cout << "\nAccessing data now . . . .\n"
                   << "\nUnable to access without password.\n"
                   << "\nRedirecting you to secondary menu . . .\n";
          break;

        case 2:
          char yesno2;
          cout << "Welcome, Jerald Dawson.\n"
                 << "Would you like to modify the employee files( y/n )? ";
          cin >> yesno2;
          cout << endl;

          if( yesno2 == 'y' )
            cout << "\nAccessing data now . . . .\n"
                   << "\nUnable to access without password.\n"
                   << "\nRedirecting you to secondary menu . . .\n";
          break;

        case 3:
          char yesno3;
          cout << "Welcome, Adeola Odunsi.\n"
                 << "Would you like to modify the employee files( y/n )? ";
          cin >> yesno3;
          cout << endl;

          if( yesno3 == 'y' )
            cout << "\nAccessing data now . . . .\n"
                   << "\nUnable to access without password.\n"
                   << "\nRedirecting you to secondary menu . . .\n";
          break;

        case 4:
          char yesno4;
          cout << "Welcome, Ciara Carey.\n"
                 << "Would you like to modify the employee files( y/n )? ";
          cin >> yesno4;
          cout << endl;

          if( yesno4 == 'y' )
            cout << "\nAccessing data now . . . .\n"
                   << "\nUnable to access without password.\n"
                   << "\nRedirecting you to secondary menu . . .\n";
          break;

        case 5:
          char yesno5;
          cout << "\nWelcome, current employee.\n"
                 << "Would you like to view information( y/n )?\n";
          cin >> yesno5;

          if( yesno5 == 'y' )
            viewExternal();
          break;

        case 6:
          cout << "\nWelcome, former employee."
                 << "\nYou need permission to access this information."
                 << "\nPlease see an owner in order to access the information."
                 << "\nThank you."
                 << "\nRedirecting you to secondary menu . . .\n";
          break;

       case 7:
         cout << "\nWelcome, new employee.\n"
                << "At this time, you need to view this information only\n"
                << "while a current employee or an owner is present.\n"
                << "\nThank you for your interests.\n";
         break;

       default:
         cout << "\nAn incorrect employee code was entered."
                << "\nEnter a correct code at prompt.\n";
         break;
    }
    break;

    case 3:
      string owner;

      string own1;
      string own2;
      string own3;
      string own4;

      ownerNames( own1, own2, own3, own4 );

      cout << "\nPlease enter password: ";
      cin >> owner;

      if( owner != own1 || owner != own2 || owner != own3 || owner != own4 )
      {
        int misspass = 1;

        while( misspass != 3 )
        {
          cout << "\nIncorrect password."
                 << "\nAttempt " << misspass << " of 3"
                 << "\nEnter a correct password: ";
          cin >> misspass;

          misspass++;
        }
      }

      if( owner == own1 || owner == own2 || owner == own3 || owner == own4 )
        cout << "Welcome, " << owner << ".\n"
               << "\nPlease enter data into the file: ";
      workExternal();
      break;

  }
}

void Users::workExternal()
{
  ofstream outJJACFile( "JJAC.dat" );

  if( !outJJACFile )
  {
    cerr << "File could not be opened.";
    exit( 1 );
  }

  double pay;
  string position;
  string name;

  cout << "Please enter the employee's name, position, and pay: ";
  cin >> name >> position >> pay;

  while( cin >> name >> position >> pay )
  {
    outJJACFile << name << ' ' << position << ' ' << pay;
    cout << "?";
  }
}

void Users::viewExternal()
{
  ifstream inJJACFile( "JJAC.dat", ios::in );

  if( !inJJACFile )
  {
    cerr << "File could not be opened.";
    exit( 1 );
  }

  string name;
  string position;
  double pay;

  cout << "\nPulling up data: \n";

  cout << "Name of Employee" << setw( 5 ) << "Position" << setw( 5 ) << "Pay"
       << endl << fixed << showpoint;

  do
  {
    cout << left << setw( 10 ) << name << setw( 13 ) << position
         << setw( 7 ) << setprecision( 2 ) << right << pay << endl;
  } while( inJJACFile >> name >> position >> pay )
}
Last edited by CDCAREY089 : December 2nd, 2008 at 09:20 AM. Reason: Replacing old text with new program text
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  #4  
Old December 4th, 2008, 07:36 AM
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Bobidybob Bobidybob is offline
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You're missing a closing bracket somewhere in your users() function.
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