Littel problem

Hey, I'm making for my study my first C++ program and I have a program whitch a if statement.

......
cin >> jaar;
if ( (jaar < 1900) || (jaar > 2100) );
{
cout << "Dit jaartal is ongeldig. Toegang Geweigerd. \n";
return 0;
}
.....
this is the statement waht is troubling me.
When I enter 1987 for the integer the if statement is still activate. I want that the program ignore the if statement when the integer "jaar" is between the value 1900 and 2100.
But it doesn't work. Can somebody tell me waht I doing wrong?

Hi,
I didn't quite understand what do you want to say?Please elaborate!

Costas

what I wanted to say is,

1. I have a integer called jaar. (dutch word for year but oke )
2. when you enter a value for "jaar" that is < 1900 or > 2100 the program will preform
cout << "Dit jaartal is ongeldig. Toegang Geweigerd. \n";
return 0;
But when the value entered for "jaar" is 1900 >= jaar or 2100 <= jaar. the program must ignore the If-statement. But the problem I have that for wahtever value I enter the program runs
cout << "Dit jaartal is ongeldig. Toegang Geweigerd. \n";
return 0;

My question is how can I fix that.

You need an else:
else
{
cout << "Whatever, here";
}

you have your return 0 inside the if statement. Put that at the end of the program, should be the last thing.

cin >> jaar;
if ( (jaar < 1900) || (jaar > 2100) );
{
cout << "Dit jaartal is ongeldig. Toegang Geweigerd. \n";
return 1;
}
else
{
cout << " ";
}

when I put a else with a random command my compiler gives the error C2181: illegal else without matching if. What is the problem with that error?

There shouldn't be a ; after the if condition. What the program says is: If jaar < 1900 or jaar > 2100 -- do nothing (since the semicolon's there). Then, cout and return. So take out the semicolon.

Yes, ubergeek is right; you don't put ; at the end of any condition. Why I didn't see it at first time.

Yeah, same here, costas -- a very hard error to catch. I didn't see it until I saw the error C2181 above.