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Old August 30th, 2006, 12:24 AM
brad sue brad sue is offline
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Loop problem

Hi ,
I have this problem I need to code in C++:

we want to know how many candies you can have with a certain amonut of money.
Each candy costs $1 and at each candy purchase, you receive 1 coupon.
You can redeem 1 candy with 7 coupons.

If you have $20, you can have 23 candies.
20/7=2 more candies from the coupons=2 more coupons.
then 20%7=6 coupons remain.

6+2=8 coupons with which you can have 1 candy.

So 20+2+1=23 candies in total.

I try to use the modulo ("%") but still I cannot find the answer. Iwant to use a loop.
this what I did. I found 22 bars instead of 23.

#include<iostream>
using namespace std;

int main()
{
int money,n;
int s,finish;

cout<<" Enter the total amount of money ";
cin>>money;
do
{
s=(money/7)+(money%7);
n=money+(money/7);
}
while(s<7);

cout<< "bar "<<n;
cout<<endl;

cin>>finish;// keep the output window open

return 0;
}

Do you have an idea?
Thank you
B

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  #2  
Old August 30th, 2006, 03:57 AM
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Itsacon Itsacon is offline
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Try this:

C Code:
Original - C Code
  1. #include <stdio.h>
  2. int main()
  3. {
  4.     int candies, coupons, money;
  5.  
  6.     /*  20 bucks to start with    */
  7.     money = 20;
  8.  
  9.     /*  1 dollar is really 7 coupons: */
  10.     for(coupons = money * 7, candies = 0; coupons > 7; coupons -= 6, candies++);
  11.  
  12.     /*  output results    */
  13.     printf("You bought %d candies. You now have rotting teeth\n", candies);
  14.     printf("You have %d coupons left\n", coupons);
  15.  
  16.     /*  terminate */
  17.     return 0;
  18. }
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Icon agrees: nice oneliner, which is not even confusing, which oneliners can be
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This is my code. Is it not nifty?

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