Please help this newb at C++

I just bought a book a couple of days ago, and I am wondering why one of the programs won't work.
Here is the part of the script I am having trouble with.
int x;
cout<<"\nHow many of x? ";
cin>>x;
cout<<"x: " <<x<<endl;

Every time I enter something for the value of x, the program closes itself out. It goes on if there is another cin statement, but it seems awkward to press enter a value and press enter to exit the program.
It does the same thing on all of the scripts with cin that I have really looked at. It lets me enter it, it goes down to the next cin, and it exits right after the cin bypassing all other things in the program.
How do I get it to just go on without having to place another cin statement further down?

I assume you're starting the program from windows explorer.

Try starting it from a dos prompt (Start->Run->'cmd', enter).

That way, the window won't close after the program has finished.

I typed it in Dev-C++ and just compiled and ran it from there.

In that case you have to add another cin, so it waits before closing.

If you need a little more info. on what I am trying to say here,
I am using the bloodshed Dev-C++ compiler, and here is an example of the script showing all of the things needed to show you what I mean.

#include<iostream>
using namespace std;
int main()
{
int x;
cout<<"what is the value of x? ";
cin >> x;
cout<<"x is" <<x<<endl;
cout<<"Press enter to exit!";
cin.ignore(cin.rdbuf()->in_avail()+1);
return 0;
}

When I enter the value for x (say 50), It just closes the program out, and it won't show what x equals in the cout command.

That is, because the terminal window in which the program is running, closes as soon as it detects the program has finished running.

There are two solutions to this:

1. You add something at the end of the program to pause it while you read the output. The extra cin accomplishes this, since the program waits for more input before finishing.
2. You start the terminal program SEPERATELY form DevCpp, and run the program by going to the directory and executing the binary (.exe). Since the terminal program is already running, it won't close upon completion, but simply return to the command prompt, allowing you to start the program again, start another program, or do whatever the hell you like (That's what terminals do, they let you do what you want to do).

If you don't know how to operate a DOS terminal, search for a tutorial on the net.

Thanks for taking the time for helping me out.

No problem.

You can also type in

system ("PAUSE");

at the end of your code, right before the return 0.
This will pause the screen and display a prompt "Press any key to continue..." which will exit the program.