:( Unkown Error!

I have no clue what is wrong, something to do witht the "char" maybe? I an a stUpiD n00b.... I have no clue what is going on... Well, Here is my code, it is just something that I thought of:

#include "iostream.h"

void dispmenu(int menu)
{

if(menu = 1){

//system("cls");
cout << "Calculator" << endl;
}
if(menu = 2){
char *ftp_pass = "";

cout << "Please Enter Password: ";
cin >> ftp_pass;

if(ftp_pass = "31337"){

cout << "1. Ping" << endl;
cout << "2. Net Send" << endl;

}

}

}

int main()
{
//Define Vars ftp_ is just so I know that I defined the var
char *ftp_name = "";
int ftp_menu = 0;

//Get Name From User
cout << "Please Enter Your Name: ";
cin >> ftp_name;

//Display Menu
cout << "Welcome " << ftp_name << ": X" << endl;
cout << "1: Math" << endl;
cout << "2: h4x0r" << endl;
cout << "3: Other" << endl;

//Pause
cin.get();

//Get Input From User
cout << "Please Select A Menu (1-3): ";
cin >> ftp_menu;

//GoTo: Switch Statement
switch(ftp_menu){

case 1 : dispmenu(1);
case 2 : dispmenu(2);
case 3 : dispmenu(3);

}

cin.get();

return 0;
}

Major defect I can see in your code is that your if stmt. does not contain a conditinal stmt., it is containing an assignement stmt. Hence both if stmts. outside main() will be satisfied.

Secondly, there are no break stmts. between each case in your main().

Do you get a Compilation error, a runtime error or your programm simply does not what supposed to? (after you fix what Cirus said, of course)

What cirus said. Also your code:
char *ftp_name = "";
cin >> ftp_name;
is a runtime error waiting to happen.
You've declared a pointer to a char, but no space for the character(s). Also, when you try read cin into ftp_name, it's pointed at a constant "" and that can't be changed. Try something like this instead:
char ftp_name[40]; // or however many characters you think you will need.
cin >> ftp_name;