user to enter 10,1 to 4 digit values

Hi! my name is wako and I have a problem to figure out how to code this program,may someone direct me on how to go about it.
Any hint given is acceptable,
Thanks
This is how I code it,

#include<iostream>
using namespace stdd;

int main()
{
int num,int total = 0, int i,int goodcount = 0;
for ( i = 0; goodcount < 10; i++) {
cout << "Enter a 1 to 4 digit value:";
cin>> num ;
if (num<0)
cout << "value is negative and has been skipped:\n";
else if (num>0) continue;
goodcount++;
total = total + num;
}
cout << endl << "Sum of all values is :" << total << endl;
return 0;
}

note: This program is supposed only to accept 10 positive values if negative number or a value that exceeds 4 digit number is entered it display an error message.

with a quick 2 sec scan i see that you have else if. its "else"

and you dont need the continue thing its already there..

To find the number of digits in an integer do something like this.

int counter = 0;
int num = numberToCheck;

while ( num != 0) {
num = num/10;
counter++;
}