|
|
|||||||||
|
|||||||||
|
|||||||||
| |
|||
| |||||||||
![]() |
|
|
«
Previous Thread
|
Next Thread
»
|
Thread Tools | Search this Thread | Display Modes |
|
#1
|
|||
|
|||
|
does anyone have a comment on why this will not work in some cases ?
[PHP] $TEST = mysql_fetch_array(mysql_query("SELECT * FROM USER_uploads WHERE userid = $gal")); if ($TEST[0]) { $PIC = mysql_query("SELECT * FROM `USER_uploads` WHERE userid = $gal ORDER BY time DESC LIMIT $limit"); while ($pic = mysql_fetch_array($PIC)) { $TYPE = mysql_fetch_array(mysql_query("SELECT * FROM USER_cat WHERE id = $pic[type]")); //skriver billedoverskrift print "<table width='100%' border='0' cellspacing='0' cellpadding='0'><tr><td colspan='2' width='100%' class='sub'>"; print "<a href='?side=billede&gall=$gal&host=$pic[id]'>$pic[navn] | [$TYPE[besk]]</a> |*<a href='?side=vis&fra=$USERID&til=$gal&host=$pic[id]&NA=$pic[navn]'>Tilføj til fremvisnings galleri</a>"; print "</td></tr><tr>"; print "<td width='100' align='right' valign='top'>"; //skriver billedbeskrivelsen print "$pic[beskrivelse]"; //viser billedet $dest = "uploads/tegninger/".$gal."_".$pic[id].".jpg"; print "</td><td align='left' valign='top' width='80' height='200'><a href='$dest'><img src='$dest' height='100%' width='100%'></a>"; print "</table>"; } } else {print "Denne bruger har ikke nogen tegninger";} |
|
#2
|
|||
|
|||
|
How, is it not working?
|
![]() |
| Viewing: Dev Articles Community Forums > Programming > General Programming Help > Comments ?! |
| Thread Tools | Search this Thread |
| Display Modes | Rate This Thread |
|
|
|
|