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  #1  
Old June 2nd, 2002, 10:39 PM
chumy chumy is offline
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displaying a query result

I have a search query result that is linked:
http://www.something.com/recording.php?recordid=2; I need to display the entire record from all the tables that the recordid is identifies.
So can anyone please point me on the right track to getting this done.
Thanks a lot.

Edit: Chumy - i had to change the url because it actually sent you to a porn site. (i just clicked it in front of my boss whops!)

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  #2  
Old June 3rd, 2002, 01:06 AM
Ben Rowe
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ok, now that ive finished explaining to my boss that devarticles isnt a porn site,

can you explain exactly what your trying to do, your question kinda loses me (messa not thinkin) just give us a small detailed example so i can help you with your query,

Ben Rowe

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  #3  
Old June 3rd, 2002, 05:25 AM
chumy chumy is offline
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I have a site that I am developing and I used a form submission query to get the recordid that match the keyword entered on the website and link it to a page. My problem is how I can pull the results on the page that is linked to the search result.
e.g. URL
I want to display the record on all the tables that match the recordid=5 when the link is clicked.
Thanks a million.

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  #4  
Old June 3rd, 2002, 06:03 PM
CopeLand CopeLand is offline
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Hi. First up, you need to get the recordId variable from the query string:

$recId = $_GET["recordId"]

Then you need to setup a MySQL query to grab the records from the database:

$s = @mysql_connect("localhost", "user", "password") or die("Couldnt connect");

$d = @mysql_select_db("yourDB", $s) or die("Couldnt select DB");

$r = mysql_query("select * from yourTable where recordId=$recId");

while($r = mysql_fetch_array($r))
{
// Print out records here
}

That's basically it. You would also wanna use is_numeric and some other checks to make sure recId is a valid integer.
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Old June 3rd, 2002, 08:10 PM
Ben Rowe
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instead of using
$recId = $_GET["recordId"]
u can use the global command

global $recordId;

just another thing, you could also have a if, then while statement

if($r = mysql_fetch_array($r))
{
while($r = mysql_fetch_array($r))
{
// Print out records here
}
}

that way you can have else statement if they is no records in the database that match the recordId number

else
{
echo 'o records found';
}

hope this helps

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