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for loop in an array

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  #1  
Old January 14th, 2004, 10:35 AM
DDDooGGG DDDooGGG is offline
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for loop in an array
I need to do the following any ideas:

PHP Code:
for ($i = 1; $i <= 10; $i++) {
        
$day_array = array('view_match.php?id='.$event_id, 'linked-day');
        
$day_of_event = $row['DATENUMBER'];
        
$test1 = ($day_of_event=>$day_array); //<-- THIS LINE CREATES AN ERROR

    } 
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  #2  
Old January 14th, 2004, 02:48 PM
digitallysmooth digitallysmooth is offline
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I am not seeing what it is you are trying to do here. It looks like you want to get information from $day_of_event which may be an associative array using the $day_array value as an index... is this close?

I also do not see where your for loop comes into play and where you would need to use the $i variables. Why is it looping up to 10?

Maybe you need a foreach to iterate an associative array?
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  #3  
Old January 18th, 2004, 10:19 AM
DDDooGGG DDDooGGG is offline
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Sorry my previous post was really bad, here is what i am trying to do, but without success:

PHP Code:
 $result = mysql_query("select id, match_date_time from table") or die ("Cannot select from schedule table. ".mysql_error()."");
    
    
        while (list($id, $match_date_time) = mysql_fetch_row($result)) {
           //echo "Key: $id; Value: $match_date_time<br />\n";
           $test = $id=>array('index.php?id='. $id,'linked'); // <-- THIS LINES CREATE THE ERROR
          echo $test."<br>";
        } 


Any ideas??
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  #4  
Old January 18th, 2004, 03:12 PM
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I dont understand why you're making the array...

why not just do this:
$test = "index.php?id=$id";

although if you insist on the array... try this:
$test = array('index.php?id='. $id,'linked');

if that fails, try $test[] = ...
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Old January 18th, 2004, 03:38 PM
DDDooGGG DDDooGGG is offline
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I need to create a list of arrays, which will then be put into another array.
i.e.
PHP Code:
 $page = array(array($id=>array('index.php?id='. $id,'linked'), $id=>array('index.php?id='. $id,'linked'), $id=>array('index.php?id='. $id,'linked')); 


does that make better sense.
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  #6  
Old January 18th, 2004, 04:35 PM
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I'm pretty sure this syntax here will cause an error:
$id=>array(stuff)

try simply taking the $id=> out and just doing array(stuff)
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Old January 18th, 2004, 04:47 PM
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it needs to be like this as the function requires it
$id=>array('index.php?id='. $id,'linked')

This is how it looks
PHP Code:
 $days = array(
      2=>array('/weblog/archive/2004/Jan/02','linked-day'),
      3=>array('/weblog/archive/2004/Jan/03','linked-day'),
      8=>array('/weblog/archive/2004/Jan/08','linked-day'),
      22=>array('/weblog/archive/2004/Oct/22','linked-day')
  );

while ($day <= $maxdays){
        if($weekday == 7){ #start a new week
            $calendar .= "</tr>\n<tr>";
            $weekday = 0;
        } 

but i want to get the day values from a database.
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  #8  
Old January 18th, 2004, 06:06 PM
Mike_r Mike_r is offline
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Use this function :

$array = array();

array_push ( $array, "STUFF, here it can be a sub-array too" );

Convert your code to use this function..
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