How to generate a 20 random word including 10 characters???

I made a thing like that but it is not working:

<?php
for($xl=0;$xl<20;$xl++){
$a="";$a="";
function doit() {
while ($i<10) {
$i++;
$determine = mt_rand(1,61);
if ($determine==1) {$a.="1";}
if ($determine==2) {$a.="2";}
if ($determine==3) {$a.="3";}
if ($determine==4) {$a.="4";}
if ($determine==5) {$a.="5";}
if ($determine==6) {$a.="6";}
if ($determine==7) {$a.="7";}
if ($determine==8) {$a.="8";}
if ($determine==9) {$a.="9";}
if ($determine==10) {$a.="a";}
if ($determine==11) {$a.="b";}
if ($determine==12) {$a.="c";}
if ($determine==13) {$a.="d";}
if ($determine==14) {$a.="e";}
if ($determine==15) {$a.="f";}
if ($determine==16) {$a.="g";}
if ($determine==17) {$a.="h";}
if ($determine==18) {$a.="i";}
if ($determine==19) {$a.="j";}
if ($determine==20) {$a.="k";}
if ($determine==21) {$a.="l";}
if ($determine==22) {$a.="m";}
if ($determine==23) {$a.="n";}
if ($determine==24) {$a.="o";}
if ($determine==25) {$a.="p";}
if ($determine==26) {$a.="q";}
if ($determine==27) {$a.="r";}
if ($determine==28) {$a.="s";}
if ($determine==29) {$a.="t";}
if ($determine==30) {$a.="u";}
if ($determine==31) {$a.="v";}
if ($determine==32) {$a.="w";}
if ($determine==33) {$a.="x";}
if ($determine==34) {$a.="y";}
if ($determine==35) {$a.="z";}
if ($determine==36) {$a.="A";}
if ($determine==37) {$a.="B";}
if ($determine==38) {$a.="C";}
if ($determine==39) {$a.="D";}
if ($determine==40) {$a.="E";}
if ($determine==41) {$a.="F";}
if ($determine==42) {$a.="G";}
if ($determine==43) {$a.="H";}
if ($determine==44) {$a.="I";}
if ($determine==45) {$a.="J";}
if ($determine==46) {$a.="K";}
if ($determine==47) {$a.="L";}
if ($determine==48) {$a.="M";}
if ($determine==49) {$a.="N";}
if ($determine==50) {$a.="O";}
if ($determine==51) {$a.="P";}
if ($determine==52) {$a.="Q";}
if ($determine==53) {$a.="R";}
if ($determine==54) {$a.="S";}
if ($determine==55) {$a.="T";}
if ($determine==56) {$a.="U";}
if ($determine==57) {$a.="V";}
if ($determine==58) {$a.="W";}
if ($determine==59) {$a.="X";}
if ($determine==60) {$a.="Y";}
if ($determine==61) {$a.="Z";}
}
return $a;

$b=doit();
echo $b;
}

}
?>

i dont think that you can define a function inside a for statement!

you can the first time, but then each time after that it will give you an error saying function already defined or something.

dude, u have to learn about switch asap

there's a tutorial on password generation at phpbuilder.com - give it a shot.