parse error doubt

Hi guys,

May i know whats wrong with my code ?

code:
$reference = "<a name=\""".$row['bookmark'].""\"></a>";


I am actually trying to output the php as:
<a name="value"></a>
in my file..

please advise.

too many double quotes...

try this:
$reference = "<a name=\"".$row['bookmark']."\"></a>";

thanks for your advise...

Another thing i wanna ask is, why we can use two time open and close doube quotes ? I was told that i can't do that..
e.g:
echo "hehe "$_REGISTER['name']". How are you " <- i can't do this right ? and i was told i should use:
echo 'hehe "$_REGISTER['name']". How are you'

but this seems working:
"<a name=\"".$row['bookmark']."\"></a>";

May i know when actually i can't use double quote twice and under which circumstances i can use it ?

Please advise.

its a matter of preference i would say and its up to u to decide what u want to use

single quotes won't interpret variables...

so:

$var = "hello";

print '$var';
print "$var";


The first line prints the variable name, the second line would print the value...


Your example should work, except your missing a .

echo "hehe ".$_REGISTER['name']". How are you";

i believe it should be

echo "hehe ".$_REGISTER['name']." How are you";

not

echo "hehe ".$_REGISTER['name']". How are you";

Bruski,
You're right, I didn't notice...

Looks like I copied the line from Alicia's post and forgot to make that change.

Thanks for the correction

np ... =]