passing the name of a form

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May 20th, 2003, 06:41 AM

tobycatlin

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passing the name of a form

I am writing my own generic form processor and it is all going well but i am stuck on how to get the name of the form that is being processed by my script.
Anyone got any ideas?

cheers toby

May 20th, 2003, 12:47 PM

jpenn

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You send the form name in a hidden field...

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May 20th, 2003, 01:30 PM

tobycatlin

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I didn't want to do that as i was using $_post to create the SQL insert statements and extra posted variables kept messing them up.
I wanted to use the form name as the name of the table that the form data would go into.
what i have done is passed the form name as a hidden field and the used unset() to destroy it before being used for the SQL.

May 21st, 2003, 09:45 PM

avit

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Just curious,

How does the form name being in $_POST get in the way of your SQL statement? I mean, don't you have to call each element in $_POST by name anyway?

May 23rd, 2003, 12:07 PM

tobycatlin

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PHP Code:


		
			
 $sql=  "CREATE TABLE $table_name (ID int NOT NULL auto_increment";

    

    while(list($key,$value)= each($_POST)) {

        if (($key != "Submit") | ($key != $input_table)) {

            $sql .= ", $key  TEXT";

        }

    }



    $sql .= ", PRIMARY KEY (ID))";

I use the above statement to generate the INSERT statement. So if anything is posted that can't be inserted the statement fails. The if statement filters out the submit value and i was getting into trouble adding extra conditional statements

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