$_POST['submit'] problem

Hi.. I'm pretty new to this..

I am trying to make a login script, where I check if the login form has been submitted by using if ($_POST['submit'])...
For some reason, it always turns out with $_POST['submit'] not being set... If I try to check for the username text field being set, like this: $_POST['username'], it works fine...

Any ideas why??

Are you actually naming your submit field? I know that I often neglect to set it. And, well, why not just check for $_POST['username'] or $_POST.

Yes.. I have set the submitnutton name to "submit".. I have also checked for any spelling mistakes a thousand times...

I could use $_POST['username'].. It just bothers me that it doesn't work, when I don't know why...

Besides, I also use the same method in my register script...

I use if $_POST['submit'] where I check for any blank input fields and other errors, and display the error messages..
and else to display the reg.form...

If I use for example $_POST['username'], and the user forgets to fill in that field before hitting the submit button, then the reg.form will be displyed without displaying the error messages...

Just use $_POST, then. I think that array should exist on post, though the values in the individual fields may be blank. Also, have you considered giving your submit button a different name? I doubt that's the problem, but it might be worth a shot. Is your submit button a button or an image? If it's an image, you'll need to use submit.x or submit.y to test for the button.

Yes.. The submit button is an image.. How do I use submit.x or .y??

something like this?

if ($_POST['submit.x'])

Thanx

I tried using just $_POST like you said, and it worked perfectly..

Thanx a lot..