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  #1  
Old May 29th, 2008, 05:35 AM
Praki4u Praki4u is offline
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Challenge for SQL Query Experts...

Challenge for SQL Query Experts...



I Created one table like...

create table Reports(ID numeric(5),[Desc] nvarchar(50),Parameters xml)

and I inserted 2 Records like...

insert into Reports(1,'customer','

<Report Name="Report Name">

<Parameters>

<Parameter ID="1" Name="ID"/>

<Parameter ID="2" Name="NAME"/>

<Parameter ID="3" Name="DOB"/>

<Parameter ID="4" Name="AGE"/>

</Parameters>

</Report>')

insert into Reports(2,'bank','

<Report Name="Report Name">

<Parameters>

<Parameter ID="1" Name="ID"/>

<Parameter ID="2" Name="NAME"/>

<Parameter ID="3" Name="ACCOUNT"/>

<Parameter ID="4" Name="BALANCE"/>

</Parameters>

</Report>')

Now My Question is How to get the distinct parameters in the 'Reports' Table like......

ID

NAME

DOB

AGE

ACCOUNT

BALANCE

What is the SQL Query ?????????????

Thanks in Advance :-)

Prakash.C

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  #2  
Old May 29th, 2008, 09:26 AM
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dykebert dykebert is offline
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I haven't used sql server and xml, but there is a good article on MSDN on using it.

http://msdn.microsoft.com/en-us/library/ms345117.aspx

Hope this helps.

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  #3  
Old July 14th, 2008, 08:51 AM
ryanrandall ryanrandall is offline
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Code:
select distinct c.value('@Name', 'varchar(100)') as name
from reports cross apply Parameters.nodes('//Parameter') T(c)

Or with some semi-intelligent ordering...

Code:
; with a as (
  select c.value('@Name', 'varchar(100)') as name, c.value('@ID', 'int') as id
  from reports cross apply Parameters.nodes('//Parameter') T(c))
select name from a group by name order by avg(1.0 * id)

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