help with PHP, MySQL

while ($rad=mysql_fetch_array($result))
{
$echo_arhnr[$m]=$rad["arhnr"];
echo "<A HREF='lugem.php'>$echo_arhnr[$m]</A> , ";}
---
I made variables from MySQL database as links. It should look like this:

Link1 , Link2 , Link3 ,

If user clicks on one of these links, he is directed to a new page called 'lugem.php'
How can I define, which link he clicked? Because, I want that page ('lugem.php') to display the information requested from MySQL db under the clicked link variable.

To make it clear:
user clicks Link2. He is directed to 'lugem.php'. Now PHP should request data from MySQL for this Link2.

eh, English is hard :/

thx.

the way I would do this is using HTTP-GET (also known as URL Rewriting)

Here's an example which reads the label for the link and an id or information for the other page...

If you can do better, Spongy, step up. No point in harrassing the moderators, who volunteer time to help people all over the forums and so sometimes miss a line of code in their haste to move to the next floundering programmer's problem.

Alright, looking at my post I did miss something...
echo "<A HREF='page.php?id=".$data['id']."'>".$data['id']."</A> , ";

I don't understand what else you want?

page.php would need a way to handle the query string... typically $_GET['id'] (from my example)...
for example: $result=mysql_query("SELECT * FROM table WHERE id=".$_GET['id']);

If you know how this works, did i misinterpet your question?

This is indeed the best way to handle such a problem.
I'm sorry, MadCozDzz...
BTW: this was not my question....

tox,
does this answer your question?

Spongy,
no hurt feelings

Yes it does, and thank You. And also I'm sorry I didn't get to respond to this post earlier, I was at home all weekend, and have no access to internet over there.

I'm sorry and thanks.

Tox