|
|||||||||
|
|||||||||
|
|||||||||
| |
|||
 |
|
|
|
|
|||||||||
|
|||||||||
|
|||||||||
| |
|||
|
|
|
|
| |||||||||
 |
|
|
«
Previous Thread
|
Next Thread
»
|
Thread Tools | Search this Thread | Display Modes |
Dev Articles Community Forums Sponsor:
|
|
Stay one step ahead of the competition. Evaluate and give feedback
on some of the hottest web development tools on the market today.
Make your opinion heard! Click
Here
|
|
#1
May 25th, 2005, 08:42 AM
|
|||
|
|||
|
How to? (Order birthday results)
I'm trying to create a list of upcoming birthdays in my family, but I can't seem to figure out how to order the query results the way I want them.
Instead of ordering them from January 1st to December 31st (which I've already figured out how to do), I want to order the results from the current day forward into the next year and then only display the top five. Here's an example of what I want the results to look like... ------------------------------------- Happy Birthday Mark! Bob turns 20 on June 6 Emily turns 23 on June 7 Fred turns 60 on August 23 Josephine turns 13 on September 31 ------------------------------------- I want the top result to say "Happy Birthday Whoever" only if it's that person's birthday on the day that the database is queried. After that day it should go back to "Whoever turns (age) on (date)" until their birthday comes up. A similar question was asked on this forum and answered back in '03, but the only difference is I'm wanting to have each person's birthdate (year included). That way I can say how old they are. It would work if all the dates were with the same year, but that's not the case. Any help would be greatly appreciated. - JC2 <><
|
|
#3
May 25th, 2005, 11:01 AM
|
|||
|
|||
|
But wouldn't that mess up because of the different birthyears?
If I have a birthday field with the "date" type, then each birthday will have a different year. I need some way to extract just the month and the day, then compare it with the current month and day of this year so that it will only display the next five birthdays from today on.
|
|
#4
May 25th, 2005, 04:06 PM
|
|||
|
|||
|
Try:
Code:
SELECT
foo
FROM
table
ORDER BY
IF( DAYOFYEAR(birthday) >= DAYOFYEAR(CURDATE()),0,1),
DAYOFYEAR(birthday) ASC
LIMIT 5
__________________
"A pawn is the most important piece on the chessboard -- to a pawn"
|
|
| Viewing: Dev Articles Community Forums > Databases > MySQL Development > How to? (Order birthday results) |
| Thread Tools | Search this Thread |
| Display Modes | Rate This Thread |
|
|
 |
|
|
Del.icio.us
Digg
Google
Spurl
Blink
Furl
Simpy
Y! MyWeb
Linear Mode
