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Variables in mysql_query

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  #1  
Old December 30th, 2003, 02:23 PM
moose1226 moose1226 is offline
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Variables in mysql_query
I have a mySQL table with fields called 'title', 'body', and 'ID'(auto incrementing).

Title ($title) and Body ($body) are input by the user on another page and the data is submitted to the page in question. Both $title and $body are strings.

what do I need to put in the mysql_query() function in order to make mySQL insert a row with the value of the variable $title in the field 'title' and the value of the variable $body in the field 'body'.

All my attempts so far have either done nothing, resulted in parse errors, or created a row with the variable names in the database, and not the actual values.
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  #2  
Old December 30th, 2003, 09:20 PM
laidbak laidbak is offline
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Post your code and I will fix it.
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  #3  
Old December 30th, 2003, 09:49 PM
moose1226 moose1226 is offline
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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>Untitled Document</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
</head>

<body>
Thank You For Your Submission
<?php
//$sqluser and $sqlpass are in the code and are correct, I just
//chose not to include it in the forums.
$database = 'groeneman_com_-_news'; //your database name

$db = mysql_connect("localhost","$sqluser","$sqlpass");
@mysql_select_db($database,$db) or die(mysql_errno() . ": " . mysql_error(). "");
$sql = 'INSERT INTO `test` ( `title` , `BODY` , `ID` ) '
. 'VALUES ( \'$title\', \'$body\', \'\' );'
. '';

?>
</body>
</html>
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  #4  
Old December 31st, 2003, 12:11 AM
laidbak laidbak is offline
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PHP Code:
<?php
//$sqluser and $sqlpass are in the code and are correct, I just
//chose not to include it in the forums.
$database = 'groeneman_com_-_news'; //your database name

$db = mysql_connect("localhost","$sqluser","$sqlpass");
@mysql_select_db($database,$db) or die(mysql_errno() . ": " . mysql_error(). "");
$sql = 'INSERT INTO `test` ( `title` , `BODY` ) ' . "VALUES ( '$title', '$body' )";
mysql_query($sql,$db) or die(mysql_errno() . ": " . mysql_error(). ""); 
?>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>Untitled Document</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
</head>

<body>
Thank You For Your Submission
</body>
</html>
__________________
__________________________________________________ _
Wil Moore III, MCP | Integrations Specialist | Senior Consultant
Are You Listed...? | DigitallySmooth Inc.
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  #5  
Old December 31st, 2003, 06:41 AM
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dhouston dhouston is offline
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Left off the mysql_query() part, Wil. You just need to run mysql_query($sql,$db) (check the parameter order) after setting $sql.
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  #6  
Old December 31st, 2003, 12:08 PM
laidbak laidbak is offline
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Talking
Quote:
Left off the mysql_query() part,
LOL... I would, wouldn't I... Good catch D.
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  #7  
Old January 4th, 2004, 12:06 PM
moose1226 moose1226 is offline
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Thanks
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