Check Remote File MIME Type Using PHP

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November 2nd, 2003, 08:56 AM

nkunicki

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Check Remote File MIME Type Using PHP

Hi, I'm making a script which takes a the URL of an MP3 file from the querystring and streams it. It works as below, but I want to be able to check the MIME type of the specified file before streaming it. Any help appreciated. Here's the code I have at the moment:

Code:

<?php
	$MP3File = $_GET["filename"];
	if ($MP3File != "") {
		if (@fclose(@fopen($MP3File, "r"))) {
			header("Content-type: audio/x-mpegurl");
			print($MP3File);
		} else {
			print("Error: Specified Filename Not Found");
		}
	} else {
		print("Error: No Filename Specified");
	}
?>

November 2nd, 2003, 09:50 AM

manoloweb

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Hello,

You should be able to do that using :

PHP Code:


		
			
 $myfile=fopen("http://www.yoursite.com/mp3/song1.mp3");

$myfileHeaders=file_get_wrapper_data($myfile); 

print_r ($myfileHeaders);

(I think you need PHP 4.3.X +)

Hope it helps

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November 2nd, 2003, 10:00 AM

nkunicki

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Hi, thanks for the reply. I get this when I run that code:

Fatal error: Call to undefined function: file_get_wrapper_data() in c:\apache\apache\htdocs\music_headers.php on line 4

I'm running PHP 4.3.2, any ideas?

November 2nd, 2003, 10:30 AM

manoloweb

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Wow,

Maybe it need a special configuration, have you tried $http_response_header()?

November 2nd, 2003, 10:39 AM

manoloweb

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I found this in my CHM manual's user contributed notes:

PHP Code:


		
			
 $file = new GetWebObject("de.php.net", 80, "/");

 $data = $file->get_header();

 echo $data["status"];

 echo $data["Content-Type"];

 

 echo $file->get_content();

class GetWebObject

{

 var $host  = "";

 var $port  = "";

 var $path   = "";

 var $header = array();

 var $content = "";

 function GetWebObject($host, $port, $path)

 {

   $this->host = $host;

   $this->port = $port;

   $this->path = $path;

   $this->fetch();

 }

 

 function fetch()

 {

   $fp = fsockopen ($this->host, $this->port);

   

   if(!$fp)

   { die("Could not connect to host.");}

   

   $header_done=false;

   

   $request = "GET ".$this->path." HTTP/1.0\r\n";

   $request .= "User-Agent: Mozilla/4.0 (compatible; MSIE 5.5; Windows 98)\r\n";

   $request .= "Host: ".$this->host."\r\n";

   $request .= "Connection: Close\r\n\r\n";

   $return = '';

   

   fputs ($fp, $request);

   

   $line = fgets ($fp, 128);

   $this->header["status"] = $line;

   

   while (!feof($fp))

   {

     $line = fgets ( $fp, 128 );

     if($header_done)

     { $this->content .= $line;}

     else

     {

       if($line == "\r\n")

       { $header_done=true;}

       else

       {

         $data = explode(": ",$line);

         $this->header[$data[0]] = $data[1];

       }

     }

   }

   

   fclose ($fp);

 }

 

 function get_header()

 { return($this->header);}

 

 function get_content()

 { return($this->content);}

}

November 2nd, 2003, 10:52 AM

nkunicki

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Thanks for the help guys, but I managed it with this:

Code:

	$FileString = $_GET["filename"];

	if ($FileString != "") {
		$FilePointer = fopen($FileString, "r");
		if (!$FilePointer) {
			die("Error: Could Not Open Specified Filename");
		} else {
			$FileHeaders = stream_get_meta_data($FilePointer);
			$IsMP3File = 0;
			foreach ($FileHeaders as $FileHeader) {
				foreach ($FileHeader as $HeaderValue) {
					if (strpos(strtolower($HeaderValue), "audio/mpeg")) {
						$IsMP3File = 1;
					}
				}
			}	
			if ($IsMP3File == 1){		
				header("Content-type: audio/x-mpegurl");
				print($FileString);
			} else {
				die("Error: The Specified Filename Is Not In MP3 Format");
			}
		}
	} else {
		die("Error: No Filename Specified");
	}

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