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  #1  
Old August 27th, 2003, 01:36 AM
lobos34 lobos34 is offline
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Creating columns in a PHP page

Hello again everyone,

I could really use some help with a php page I am trying to design.

What I want to do:
I am working on a review web site for a friend, I would like to pull the fields (lets say "image", "company" and "title" and then have them link to the reviews ) from the MySQL database, have them show up in the browser 5 rows down and 5 col across. I have the 5 rows down working perfectly. I cannot for the life of me get 5 col across. Here is the code I have working (Only 3 rows down at this time).



PHP Code:
<?php
         
include("header.inc");
        
// display individual record

        
if ($id) {

       
$result mysql_query("SELECT * FROM reviews WHERE id=$id",$db);

        
$myrow mysql_fetch_array($result);
   
         echo 
"<center><br><table border=0 width=650>\n";
   
        
printf("<tr><td>%s &nbsp; &nbsp; &nbsp; &nbsp;%s </td><td>"$myrow["image"], $myrow["mpgs"]);
   
     
printf("%s\n<br><tr><td>"$myrow[""]);
   
     
printf("<b>Title:</b> %s\n<br><tr><td>"$myrow["title"]);
   
     
printf("<b>Company:</b> %s\n<br><tr><td>"$myrow["company"]);
    
     
printf("<b>Cast:</b> %s\n<br><tr><td>"$myrow["cast"]);

     
printf("<b>Director:</b> %s\n<br><tr><td>"$myrow["director"]);
   
     
printf("<b>Review:</b> %s\n<br><tr><td>"$myrow["review"]);
   
     
printf("<b>Links:</b>%s\n<br><tr><td>"$myrow["links"]);
   
     echo 
"</td></tr></table></center>\n";
} else {

    
// show employee list

   
$result mysql_query("SELECT * FROM reviews",$db);

    if (
$myrow mysql_fetch_array($result)) {

      
// display list if there are records to display

      
do {
       echo 
"<center><br><table border=1 width=250><tr>\n";
       
printf("<td><a href=\"%s?id=%s\">%s\n %s</a></td>\n"$PHP_SELF,$myrow["id"],$myrow["title"],$myrow["company"]);
       echo 
"</table></center></tr>\n";
       
      } while (
$myrow mysql_fetch_array($result));
       
    } else {
        
      
// no records to display

      
echo "Sorry, no records were found!";    

    }

     }

      include(
"footer.inc");

       
?>


I can get this to work perfect, but I cannot figure out how to get 5 colomns across.

Any help or php snipets Even a link to a tutorial on how to create cols in php. would be appreciated

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  #2  
Old August 27th, 2003, 06:17 PM
digitallysmooth digitallysmooth is offline
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This snippet should help you (taken from: http://laidbak.net/phpsample/columnsplit/)
Code:
<table border="2">
<th colspan="100%">Raw Index Sample</th>
<?php
    for ($row=1; $row <= $numrows; $row++)
    {
        // Initialize Cells
        $cell = 0;
?>
        <tr>
<?php
        for ($col=1; $col <= $numcols; $col++)
        { 
?>
                <td>
<?php 
    if ($col===1) {
        print $cell += $row;
    } else {
        print $cell += $numrows; 
    }
?>
        </td>
<?php
        }
?>
        </tr>
<?php
    }
?>
</table>
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  #3  
Old August 27th, 2003, 07:30 PM
lobos34 lobos34 is offline
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Thanks laidbak,

I am sort of new at this so (at the risk of sounding stupid) exactly where in the code above would I put your code. I tested it a couple of times and got it to put the rows using your table
example:
title company
title company
title company
But what I want is :
title company | title company | title company

if you could tell me where to put it in the code I would appreciate it.

Thanks

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  #4  
Old August 27th, 2003, 10:04 PM
digitallysmooth digitallysmooth is offline
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Whatever you want output in horizontally you will need to put between the:

<td> </td>

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  #5  
Old August 27th, 2003, 10:51 PM
lobos34 lobos34 is offline
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Thanks for the info laidbak, but I am still getting it in rows not columns.

This is where I am confused:
you said put what I want Horz between the: <td> </td>
I did that and it worked fine but still only in rows. You have this in between there
PHP Code:
<td>
<?
php 
    
if ($col===1) {
        print 
$cell += $row;
    } else {
        print 
$cell += $numrows
    }
?>
        </td>

This is what I want to come out horz:
<?php
printf
("<a href=\"%s?id=%s\">%s\n %s</a>\n",*$PHP_SELF,$myrow["id"],$myrow["title"],$myrow["company"]);
?> 


So exactly where in between your <td></td> tags should I put it?

Thanks again

*******

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  #6  
Old August 27th, 2003, 11:45 PM
digitallysmooth digitallysmooth is offline
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Replace my print statements with yours.

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  #7  
Old August 28th, 2003, 12:09 AM
lobos34 lobos34 is offline
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Ok now it comes up blank. No error codes, nothing just three blank table rows I am at a loss.
here is the code could you take a look and see where I am screwing it up?
PHP Code:
<body>
<?
php
include("header.inc");
// display individual record

if ($id) {

   
$result mysql_query("SELECT * FROM reviews WHERE id=$id",$db);

   
$row mysql_fetch_array($result);
   
   echo 
"<center><br><table border=0 width=650>\n";
   
   
printf("<tr><td>%s &nbsp; &nbsp; &nbsp; &nbsp; %s</td><td>"$row["image"], $row["mpgs"]);
   
   
printf("%s\n<br><tr><td>"$row[""]);
   
   
printf("<b>Title:</b> %s\n<br><tr><td>"$row["title"]);
   
   
printf("<b>Company:</b> %s\n<br><tr><td>"$row["company"]);
    
   
printf("<b>Cast:</b> %s\n<br><tr><td>"$row["cast"]);

   
printf("<b>Director:</b> %s\n<br><tr><td>"$row["director"]);
   
   
printf("<b>Review:</b> %s\n<br><tr><td>"$row["review"]);
   
   
printf("<b>Links:</b>%s\n<br><tr><td>"$row["links"]);
   
   echo 
"</td></tr></table></center>\n";
} else {

    
// show employee list

   
$result mysql_query("SELECT * FROM reviews",$db);

    if (
$row mysql_fetch_array($result)) {

      
// display list if there are records to display

      
do {
       
       
?> 
       <table border=2 >
<th colspan=20%>
</th>
<?php
    
for ($row=1$row <= $numrows$row++)
    {
        
// Initialize Cells
        
$cell 0;
?>
        <tr>
<?php
        
for ($col=1$col <= $numcols$col++)
        { 
?>
                <td>

<?php 
      
if ($col===1) {
        
printf("<a href=\"%s?id=%s\">%s\n %s</a>\n"$PHP_SELF$row["id"], $row['title'], $row['company']);
    } else {
        
printf("<a href=\"%s?id=%s\">%s\n %s</a>\n"$PHP_SELF$row["id"], $row['title'], $row['company']);
    }
?>
        </td>
<?php
        
}
?>
        </tr>
<?php
    
}
?>
</table>
<?php
       
      
} while ($row mysql_fetch_array($result));
       
    } else {
        
      
// no records to display

      
echo "Sorry, no records were found!";    

    }

}

include(
"footer.inc");

?> 


Thanks

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  #8  
Old August 28th, 2003, 02:12 AM
digitallysmooth digitallysmooth is offline
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I should have been more clear... my code wasn't supposed to be copy ready. In other words, you just pasted my code and glued your code into certain spots and it is not going to work like that.

The code I gave you was for you to see how it was done... I wasn't trying to do it for you.

Basically, you need to use the foreach statement and write out the proper <tr> <td> tags and place your variables where they are to be output.

I suggest mocking this up in straight html first, then it will be a matter of sticking the proper php code in between.

time for bed... good night.

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  #9  
Old August 30th, 2003, 06:26 PM
FrankieShakes FrankieShakes is offline
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If you want to have 6 columns (3 of each heading), you should use "6" as your modulus operation...

PHP Code:
 $i = ( int )0;  // Temporary counter

while ($row mysql_fetch_array($result){
   if (( 
$i ) == 0){
     echo(
"</tr><tr>");  // This ends the row and starts a new one
   
} else {
     echo(
"<td>Col Data</td>");
   }
   
$i++;



This will create a new row everytime your counter is a multiple of 6. I hope that clears up some of the confusion...
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  #10  
Old September 24th, 2003, 12:39 AM
lobos34 lobos34 is offline
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Hey FrankieShakes

Thanks for the code it worked out great, and It only took me half a day to get it to work ( i'm such a newbe).

Half of an hour later:
oops sorry I have to take that back, it's not creating a new row. It only does one row across and stops there?

Last edited by lobos34 : September 24th, 2003 at 01:04 AM.

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  #11  
Old September 24th, 2003, 06:50 AM
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dhouston dhouston is offline
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Did you print a "<tr>" before the while and a "</tr>" after it?

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Old September 25th, 2003, 12:45 AM
lobos34 lobos34 is offline
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???????

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  #13  
Old September 25th, 2003, 06:53 AM
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FrankieShakes's code is right on, but you'll notice that it always starts each modulus (including the first loop iteration) by printing "</tr>" and ends with "</td>." That's starting in the middle of the row, and in some browsers, having malformed code like that will hose up the results. In order to fix it, do print("<tr>") before you enter the loop and print("</tr>") after you exit the loop. You might also want to print beginning and ending table tags. This may not solve the immediate problem, but it's something you should be aware of.

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Old September 25th, 2003, 04:41 PM
lobos34 lobos34 is offline
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Ok guys,

Thanks to your help I have the code working good except one problem, I even have it pulling the films by title instead of id.

Now the problem I mentioned earlier, the code FrankieShakes
gave me is pulling the films and with the info dhuston gave me, it
is continuing to the next row, but it is only printing 5 columns
instead of 6, and it is printing the 1st thru 5th fields skipping the
6th and going on to the 7th thru 11th field starting a new row. I
know after a day of fugging with it. This code and the fact that
my db starts with 0001 has something to do with the problem:


Code:
PHP Code:
 $i = ( int )0;  // Temporary counter 


here is my code
PHP Code:
<html>
<
head>
<?
php include ("header2.inc"); ?>
<br>
</head>
<body>
<table width="" border="1" align="center">
<font face="Verdana, Arial, Helvetica, sans-serif"  style="font-weight:normal" size="2">

<?php
if (@ $id) {
   
$result mysql_query("SELECT * FROM reviews WHERE id=$id",$db);
   
$myrow mysql_fetch_array($result);
   
printf("%s\n"$myrow["images"]);
   
printf("%s\n<br>", @ $myrow["mpgs"]);
   
printf("<b>Title:</b> %s\n<br>"$myrow["title"]);
   
printf("<b>Company:</b> %s\n<br>"$myrow["company"]);
   
printf("<b>Cast:</b> %s\n<br>"$myrow["cast"]);
   
printf("<b>Director:</b> %s\n<br>"$myrow["director"]);
   
printf("<b>Review:</b> %s\n<br>"$myrow["reviews"]);
   
printf("<br><b>Available:</b> %s\n"$myrow["links"]);
} else {
    
// show employee list
   
$result mysql_query("SELECT * FROM reviews ORDER BY title ASC",$db);
   
$i = (int) 0;  // Temporary counter
     
printf("<tr>");
while (
$myrow mysql_fetch_array($result)){
   if (( 
$i "6" ) == 0){
     echo(
"</tr><tr>");  // This ends the row and starts a new one
   
} else {
     
printf("<td align=center><a href=\"%s?id=%s\">%s 
<br>%s</a>\n</td>"
$PHP_SELF$myrow["id"], $myrow["title"], $myrow["company"]);
   }
   
$i++;
 }
}
     
printf("</tr>"); 
?>
</font>
</table>
</body>
</html>
<?php include ("footer.inc");
?>
</body>
</html> 


can you guys give me an idea on how to fix this?
Thanks

Last edited by lobos34 : September 25th, 2003 at 05:04 PM.

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  #15  
Old September 25th, 2003, 05:05 PM
digitallysmooth digitallysmooth is offline
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Quote:
but it is only printing 5 columns
Are you seeing the second record through the 6th or 1 - 5? That will give me a good indication where your problem is.

I have a feeling it has to do with you initializing your counter to 1 instead of 0.

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  #16  
Old September 25th, 2003, 05:30 PM
lobos34 lobos34 is offline
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I should have explained what results I received while tring to fix the problem. Changing the counter does not fix the problem it just changes the skipped result from 6 to 7.

If I leave the counter at 0 I can see results 1 thru 5 in columns 1 thru 5 but result 6 and column 6 are not printed they are skipped and result 7 starts the new row.

If I change the counter to 1 I can see results 2 thru 6 in columns 1 thru 5 but result 1 is skipped completely and result 7 ( that should be in column 6) and column 6, are not printed. result 8 starts the new row.

hope this explains the problem better.

Last edited by lobos34 : September 25th, 2003 at 05:35 PM.

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  #17  
Old September 25th, 2003, 06:02 PM
FrankieShakes FrankieShakes is offline
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Quote:
Originally posted by lobos34

if (( $i % "6" ) == 0){


Take the quotes out... Right now you're treating 6 as a string... It should be an integer value. For readability, you can also cast it to be an integer value:

PHP Code:
if (( $i % ( int ) ) == 0){ 


That should do it for you...

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Old September 25th, 2003, 06:13 PM
lobos34 lobos34 is offline
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Sorry about that I had already taken out the quotes, and there was no change. I also just tried: if (( $i % ( int ) 6 ) == 0){
and that made no difference either.

Could it be the way I have my db set up that is causing the problem? If so I would be ok with rebuilding it to the correct format if someone could tell me how...

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Old September 25th, 2003, 06:52 PM
lobos34 lobos34 is offline
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After using another script that I had made that only listed them in rows. I now belive that the problem is not the data base, The second script listed all the results, but only in rows instead of columns.
I believe the problem is in the (int) call. My reasoning is if I use a script that does not use (int) like this:
PHP Code:
 $result mysql_query("SELECT * FROM reviews",$db);

    if (
$myrow mysql_fetch_array($result)) {

      
// display list if there are records to display

      
do {
       echo 
"<center><br><table border=1 width=250><tr>\n";
       
printf("<td><a href=\"%s?id=%s\">%s\n %s</a></td>\n"
$PHP_SELF,$myrow["id"],$myrow["title"],$myrow["company"]);
       echo 
"</table></center></tr>\n";
       
      } while (
$myrow mysql_fetch_array($result));
       
    } else {
        
      
// no records to display

      
echo "Sorry, no records were found!"


it prints out all the results without skipping any.
I'm still new to this so I could be worng?

Last edited by lobos34 : September 25th, 2003 at 11:40 PM.

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  #20  
Old September 29th, 2003, 08:00 PM
lobos34 lobos34 is offline
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For anyone else having this problem, here is the fix that worked out great.


This is an extremely common mistake.

Code:
PHP Code:
if (( $i % ( int ) ) == 0){ 
    echo(
"</tr><tr>"); // This ends the row and starts a new one 
} else { 
    
printf("<td align=center><a href=\"%s?id=%s\">%s<br>%s</a></td> "
        
$PHP_SELF$myrow["id"], $myrow["title"], $myrow["company"]); 



Your "else" doesn't happen when $i % 6 == 0. So every sixth column doesn't get printed. You want to take the "else" off this structure entirely:

Code:
PHP Code:
if (( $i % ( int ) ) == 0){ 
    echo(
"</tr><tr>"); // This ends the row and starts a new one 

printf("<td align=center><a href=\"%s?id=%s\">%s<br>%s</a></td> "
    
$PHP_SELF$myrow["id"], $myrow["title"], $myrow["company"]); 



You're also making an empty table row at the beginning of your table and embedding the whole thing in an extraneous table that isn't correct HTML. Try this instead:

Code:
PHP Code:
<!-- you have a <trhere that should not be there --> 
<?
php 
if (@ $id) { 
    
// I assume all this works, so I omit it for brevity 
} else { 
    
// show employee list 
    
$result mysql_query("SELECT * FROM reviews ORDER BY title ASC",$db); 
    
$COLUMNS = (int) 6// change if you want a different number of columns 
    
$i = (int) 0
    while (
$myrow mysql_fetch_array($result)) { 
        if(
$i++ == 0) { // first column 
            
printf("<tr>"); // start a row 
        

        
printf("<td align=center><a href=\"%s?id=%s\">%s<br>%s</a></td> "
            
$PHP_SELF$myrow["id"], $myrow["title"], $myrow["company"]); 
        if(
$i == $COLUMNS) { // last column 
            
printf("</tr>");  // end a row 
            
$i 0// next column is a first column 
        

    } 
    
// "what if" cleanup code: 
    
if($i 0) { // ****, we ended in the middle of a row! 
        
while($i++ != $COLUMNS) { // for each remaining column, 
            
printf("<td>&nbsp;</td>"); // add an empty cell 
        

        
printf("</tr>"); // end the row 
    


?> 
<!-- you have a </tr> here that should not be there --> 


Thanks to CDarklock over at WWDN for the code fix.

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  #21  
Old September 30th, 2003, 06:31 PM
FrankieShakes FrankieShakes is offline
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Lobos,

Glad you got it working... I can't believe I missed the "else" on that statement!

As for the <tr>, I've never had that issue myself... My tables always display appropriately, without any extraneous tags. Weird!

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  #22  
Old September 30th, 2003, 06:49 PM
lobos34 lobos34 is offline
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FrankieShakes
Those were not your table tags. I added extra for something else that he didn't know about. he thought they were there for no reason.

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