help with site monitoring script

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May 28th, 2004, 08:45 PM

freelancer

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Join Date: May 2004

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help with site monitoring script

I've found a site monitoring script (shown below) which is used to monitor if HTTP, FTP, SMTP, POP3, MySQL, IMAP, DNS, Secondry DNS, and DHCP are running and up.
Although I always get the following warning messages when trying to run the script:

Warning: fsockopen(): unable to connect to www.domain.com:3306 in C:\Program Files\Apache Group\Apache2\htdocs\status.php on line 24
MySQL: PORT 3306 =
Warning: fsockopen(): unable to connect to www.domain.com:3306 in C:\Program Files\Apache Group\Apache2\htdocs\status.php on line 24
IMAP: PORT 143 =
Warning: fsockopen(): unable to connect to ns1.dnsjunction.com:3306 in C:\Program Files\Apache Group\Apache2\htdocs\status.php on line 24
DNS:[ns1.dnsjunction.com] PORT 53 =
Warning: fsockopen(): unable to connect to ns1.dnsjunction.com:3306 in C:\Program Files\Apache Group\Apache2\htdocs\status.php on line 24
Secondary DNS:[ns1.dnsjunction.com] PORT 53 =
Warning: fsockopen(): unable to connect to ns1.dnsjunction.com:3306 in C:\Program Files\Apache Group\Apache2\htdocs\status.php on line 24
DHCP: PORT 68 =

==============================

Script used:

<?php
$domain = "www.domain.com";
$dns_server="ns1.dnsjunction.com";
$sec_dns="ns1.dnsjunction.com";
?>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<title>Server Status</title>
</head>

<body>
Server Status 

Online:<img src="on.jpg"> 
Offline:<img src="off.jpg"> <HR NOSHADE>
<?
function lookup_ports($hport,$hdomain) {
$fp = fsockopen($hdomain, $hport,$errno,$errstr, 4);
if (!$fp){
$data = "<img src='off.jpg'>";
} else {
$data = "<img src='on.jpg'>";
fclose($fp);
}
return $data;
}
function get_server_software($domain) {
$fp = fsockopen($domain, 80, $errno, $errstr, 1);
if (!$fp) {
return("");
}
else {
fputs($fp, "HEAD / HTTP/1.1\r\nHost: " . $domain . "\r\n\r\n");
while (!feof($fp)) {
if (preg_match("/\bServer:/", $server = fgets($fp, 256))) {
fclose($fp);
return(substr($server, 8, -2));
}
}
fclose($fp);
}
}

echo "Checking services on: ".$domain;
echo " Server type :";
echo get_server_software($domain);
echo " ";
echo " <li>HTTP: PORT 80 = ".lookup_ports("80",$domain)."</li>";
echo "<li>FTP: PORT 21 = ".lookup_ports("21",$domain)."</li>";
echo "<li>SMTP: PORT 25 = ".lookup_ports("25",$domain)."</li>";
echo "<li>POP: PORT 110 = ".lookup_ports("110",$domain)."</li>";
echo "<li>MySQL: PORT 3306 = ".lookup_ports("3306",$domain)."</li>";
echo "<li>IMAP: PORT 143 = ".lookup_ports("3306",$domain)."</li>";
echo "<li>DNS:[$dns_server] PORT 53 = ".lookup_ports("3306",$dns_server)."</li>";
echo "<li>Secondary DNS:[$sec_dns] PORT 53 = ".lookup_ports("3306",$sec_dns)."</li>";
echo "<li>DHCP: PORT 68 = ".lookup_ports("3306",$dns_server)."</li>";
?>

</body>
</html>

Can someone tell me please where exactly is the error in the script, or why I am getting such warning.

Thanks in advance

June 2nd, 2004, 03:42 PM

laidbak

you know how we do

Join Date: Jun 2002

Location: In Tha IE -- San Bernardino COUNTY

Posts: 788

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Well, at first glance the code looks like it it trying to issue an HTTP request to protocols that are obviously do not understand HTTP commands.

You are better off using this script to monitor web sites / pages.

That was just from a quick glance... I did not have time to read it carefully so you might check into it.

__________________
__________________________________________________ _
Wil Moore III, MCP | Integrations Specialist | Senior Consultant
Are You Listed...? | DigitallySmooth Inc.

June 3rd, 2004, 07:10 AM

dhouston

Contributing User

Dev Articles Beginner (1000 - 1499 posts)

Join Date: May 2003

Location: Tennessee

Posts: 1,355

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Maybe prepending "@" to your fsockopen calls will suppress the error message while still giving you a return you can use to print your custom status messages.

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