Passing Variable PHP

Hi everybody
I have a problem, I have a script to save the data of a Form in a MySql Table and when I Type the Information and Click Submit I give me this error:

Notice: Undefined variable: codigo in c:\web\fernandez\agenda.php on line 45
... and it is with each field.... Ex. codigo, name, email ,etc...

I know that the name of the variable must be the same of the name of the form field. This is ok.. and I know that when you type the data and click submit, php get the value and change the variable like globlal variable,and thus it take the values and save it in the table. this is ok..
then it give me the error only in my pc but when I upload the files in the hosting and run the form, it run ok, perfectly..

I have WinXP, PHP 4.3.2, Apache 1.3.28
and it is the same of the hosting

so, I think I have some setting in the apache, I need to change, but I dont know a lot of apache..
Please if some body can help me.. I need it quickly...


thanks ..

NVM

You have your error reporting set to the highest level on your PC. That is good... do not change it.

What you need to do is check your variables. For instance:

if ( isset($_POST['name']) ) $name = $_POST['name'];
if ( isset($name) )
{
print $name;
}

If you code like that you will not get Notice errors and you will find you will be debugging a lot less. Believe me, it is worth your time.

if the notices get to be a prob for you and your code is working correctly just place a @ sign in front of the offending line.

I highly advise against this advice as you should not ignore notices for the simple fact that they are notices. Notices are there to help you. Although notices are not exactly the same as errors, notices alert you to issues that could easily become errors as your code becomes more complex. It will save the programmer time and money in the long run by not avoiding these.

Reminds me of Visual Basic "On Error Resume Next"