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#1
January 3rd, 2003, 12:44 AM
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PHP Notice Problem
Why do I get this notice? And is there any way to get rid of it?
Notice: Use of undefined constant option - assumed 'option' in c:\...etc Here is the code: Code:
<?php
$sql = MYSQL_QUERY('SELECT `option` FROM `settings` WHERE `type` = \ 'window\ ' ');
$p_window = MYSQL_FETCH_ARRAY($sql);
if ($p_window[option] == 1) //error is on this line
{
echo "window option is 1";
}
?>
Thanks for any help  Last edited by subduck : January 3rd, 2003 at 12:49 AM.
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#3
January 3rd, 2003, 05:18 AM
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you must be running your server on windows.
On windows servers when you have an array name, you must encase it in either ' or " echo $array['name']; on a linux server you dont need the ' or " but to be on the safe side, its still used. when you dont have the ' or " it asumes, its either a number, variable or constant.
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