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Problem with IF statement

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  #1  
Old August 11th, 2004, 08:28 PM
devey devey is offline
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Problem with IF statement
Hi,
I have a dropdown box like this which calls some javascript:

<select name="<?php echo $row["itemId"]; ?>" onChange="UpdateQty(this)">
<?php

for($i = 1; $i <= 10; $i++)
{
echo "<option ";
if($row["qty"] == $i)
{
echo " SELECTED ";
}
echo ">" . $i . "</option>";
}
?>
</select>


which is shown in a table along side each record listed. However i want to
only show it if say if ($amount > 1) otherwise i will echo the value 1. I have been
trying to build an if else statement around this but am struggling getting quotes/brackets
right.
Any help much appreciated
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  #2  
Old August 12th, 2004, 06:45 AM
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Itsacon Itsacon is offline
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Something like this?

PHP Code:
if($amount>1)
{
    echo "<select name=\"" . $row["itemId"] . "\" onChange=\"UpdateQty(this)\">\n";
    for($i = 1; $i <= 10; $i++) 
    { 
        echo "<option value=\"" . $i . "\"; 
        if($row["qty"] == $i) 
            echo " selected="selected\""; 
        echo ">" . $i . "</option>\n"; 
    }
    echo "</select>\n";
}
else
    echo $amount; 
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  #3  
Old August 12th, 2004, 07:38 AM
devey devey is offline
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thanks for having a go but getting the dreaded:

parse error, unexpected '\"', expecting T_STRING or T_VARIABLE or T_NUM_STRING in etc etc
error for the if($row["qty"] == $i) line
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  #4  
Old August 12th, 2004, 08:07 AM
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In the 'selected="selected"' line, the backslash preceding the first quote in front of the second "selected" isn't rendering onscreen, though Itsacon appears to have included it. Add a backslash in front of that quote to escape it.
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  #5  
Old August 12th, 2004, 08:29 AM
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Exactly, and I forgot a quote on the 7th line (in the <option> tag), this is the correct code:
PHP Code:
if($amount>1) 
{ 
    echo "<select name=\"" . $row["itemId"] . "\" onChange=\"UpdateQty(this)\">\n"; 
    for($i = 1; $i <= 10; $i++) 
    { 
        echo "<option value=\"" . $i . "\""; 
        if($row["qty"] == $i) 
            echo " selected=\"selected\""; 
        echo ">" . $i . "</option>\n"; 
    } 
    echo "</select>\n"; 
} 
else 
    echo $amount; 
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  #6  
Old August 12th, 2004, 08:59 AM
devey devey is offline
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Quote:
Originally Posted by dhouston
In the 'selected="selected"' line, the backslash preceding the first quote in front of the second "selected" isn't rendering onscreen, though Itsacon appears to have included it. Add a backslash in front of that quote to escape it.

Works great now. Thanks both of you for your help
very much appreciated.
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  #7  
Old August 12th, 2004, 03:18 PM
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You're welcome.
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