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$variable=10.00; displays as whole. Why?

Discuss $variable=10.00; displays as whole. Why? in the PHP Development forum on Dev Articles.
$variable=10.00; displays as whole. Why? PHP Development forum to discuss anything related to developing applications in PHP. Topics include architecture, coding standards, and debugging methods.

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  #1  
Old July 5th, 2004, 11:20 PM
the12php the12php is offline
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$variable=10.00; displays as whole. Why?
I Just started learning php (php newbie)

a variable value 10.00 displays as 10

I've tried $variable = round(10.00, 2)
I've delcared it a float and it still displays as a whole. I know I'm doing something wrong but can't pinpoint it.


hope someone can help

Thanks fellas!
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Old July 6th, 2004, 08:45 AM
kode_monkey kode_monkey is offline
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This is probably because php is weakly typed so just ignores the 0's after the decimal point unless they are relevent (ie have a non-zero digit after them).

Don't know if there is a way around this, what is the context its being used in?

-KM-
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Old July 7th, 2004, 03:21 AM
digitallysmooth digitallysmooth is offline
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kode_monkey is correct... PHP is not strongly-typed, thus, "10.00" can be represented easily as a numeric type or a string type. If it is represented as a numeric type, you only get the numbers that matter (10).

If you want to view it as 10.00 you will have to cast this into a string. The simple way is:

PHP Code:
<?php

$ten = 10.00;            

/* prints six zeros */
//printf('%f', $ten);

/* prints only two zeros */
printf('%01.2f', $ten);  

?>
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